From 68615a9ad2c942254135cffb00cf25a84a3b1356 Mon Sep 17 00:00:00 2001 From: Prefetch Date: Sat, 31 Dec 2022 22:21:39 +0100 Subject: Initial commit --- 24/input.txt | 28 ++++++++++++++++++++ 24/main.py | 86 ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 24/test.py | 18 +++++++++++++ 3 files changed, 132 insertions(+) create mode 100644 24/input.txt create mode 100755 24/main.py create mode 100755 24/test.py (limited to '24') diff --git a/24/input.txt b/24/input.txt new file mode 100644 index 0000000..e204f7d --- /dev/null +++ b/24/input.txt @@ -0,0 +1,28 @@ +1 +3 +5 +11 +13 +17 +19 +23 +29 +31 +37 +41 +43 +47 +53 +59 +67 +71 +73 +79 +83 +89 +97 +101 +103 +107 +109 +113 diff --git a/24/main.py b/24/main.py new file mode 100755 index 0000000..61c97a6 --- /dev/null +++ b/24/main.py @@ -0,0 +1,86 @@ +#!/usr/bin/python + +from itertools import combinations + + + +def solve_partn(partn, masses): + if partn == 1: + num_groups = 3 + else: # partn == 2 + num_groups = 4 + + m_total = sum(masses) + m_group = int(m_total / num_groups) + + # At first, it seems the easiest way is to generate all possible + # grouping of packages, and then just keep the ones that are valid, + # and find the best among the remaining configurations. However, + # the input file has 28 packages, so there are 3^28 = 23 trillion + # possible groupings, which is obviously too much to brute-force. + + # Instead, we find the candidates for group 1: subsets of the packages + # whose masses add up to `m_group', with the smallest number of items. + + # Step 1: Find all combinations of packages in a certain range + k_min = int((m_group - 1) / max(masses)) + 1 + k_max = int(len(masses) / num_groups) + combos = [] + for k in range(k_min, k_max + 1): + combos += combinations(masses, k) + # Step 2: Keep only combinations whose masses add up to `m_group' + group1 = [] + for c in combos: + if sum(c) == m_group: + group1.append(c) + # Step 3: Keep only candidates with the smallest package count + min_len = min(map(len, group1)) + smallest = {} + for g1 in group1: + if len(g1) == min_len: + smallest[g1] = [] + + # Verify for each group 1 candidate that the remaining packages can be + # divided into 2 more groups of mass `m_group'. This takes time and it + # turns out that no candidates get rejected, hence it's commented out. + #for i, g1 in enumerate(smallest): + # remaining = [] + # for m in masses: + # if m not in g1: + # remaining.append(m) + # k_max = int(len(remaining) / (num_groups - 1)) + # combos = [] + # for k in range(k_min, k_max + 1): + # combos += combinations(remaining, k) + # for c in combos: + # if sum(c) == m_group: + # smallest[g1].append(c) + #valid = {} + #for g1 in smallest.keys(): + # if len(smallest[g1]) > 0: + # valid[g1] = smallest[g1] + + # Calculate quantum entanglement of each group 1 candidate + qentangs = [] + for g1 in smallest.keys(): + qe = 1 + for m in g1: + qe *= m + qentangs.append(qe) + + return min(qentangs) + + + +def main(): + # Read package weights from input text file + with open("input.txt", "r") as f: + masses = list(map(int, f.read().splitlines())) + + print("Part 1 solution:", solve_partn(1, masses)) # 10439961859 for me + print("Part 2 solution:", solve_partn(2, masses)) # 72050269 for me + + + +if __name__ == "__main__": + main() diff --git a/24/test.py b/24/test.py new file mode 100755 index 0000000..2c2655c --- /dev/null +++ b/24/test.py @@ -0,0 +1,18 @@ +#!/usr/bin/python + +import unittest + +import main + + + +class Examples(unittest.TestCase): + def test_example1(self): + masses = [1, 2, 3, 4, 5, 7, 8, 9, 10, 11] + self.assertEqual(main.solve_partn(1, masses), 99) + self.assertEqual(main.solve_partn(2, masses), 44) + + + +if __name__ == "__main__": + unittest.main() -- cgit v1.2.3