From 06e2d1f11d2d390c3f31e4ad9cfe28ff039d075f Mon Sep 17 00:00:00 2001 From: Prefetch Date: Tue, 30 Mar 2021 17:17:39 +0200 Subject: Expand knowledge base --- content/know/concept/capillary-action/index.pdc | 129 ++++++++++++++++++++++++ 1 file changed, 129 insertions(+) create mode 100644 content/know/concept/capillary-action/index.pdc (limited to 'content/know/concept/capillary-action/index.pdc') diff --git a/content/know/concept/capillary-action/index.pdc b/content/know/concept/capillary-action/index.pdc new file mode 100644 index 0000000..e76b88a --- /dev/null +++ b/content/know/concept/capillary-action/index.pdc @@ -0,0 +1,129 @@ +--- +title: "Capillary action" +firstLetter: "C" +publishDate: 2021-03-29 +categories: +- Physics +- Fluid mechanics + +date: 2021-03-07T20:42:28+01:00 +draft: false +markup: pandoc +--- + +# Capillary action + +**Capillary action** refers to the movement of liquid +through narrow spaces due to surface tension, often against gravity. +It occurs when the [Laplace pressure](/know/concept/young-laplace-law/) +from surface tension is much larger in magnitude than the +[hydrostatic pressure](/know/concept/hydrostatic-pressure/) from gravity. + +Consider a spherical droplet of liquid with radius $R$. +The hydrostatic pressure difference +between the top and bottom of the drop +is much smaller than the Laplace pressure: + +$$\begin{aligned} + 2 R \rho g \ll 2 \frac{\alpha}{R} +\end{aligned}$$ + +Where $\rho$ is the density of the liquid, +$g$ is the acceleration due to gravity, +and $\alpha$ is the energy cost per unit surface area. +Rearranging the inequality yields: + +$$\begin{aligned} + R^2 \ll \frac{\alpha}{\rho g} +\end{aligned}$$ + +From the right-hand side we define the **capillary length** $L_c$, +so gravity is negligible if $R \ll L_c$: + +$$\begin{aligned} + \boxed{ + L_c + = \sqrt{\frac{\alpha}{\rho g}} + } +\end{aligned}$$ + +In general, for a system with characteristic length $L$, +the relative strength of gravity compared to surface tension +is described by the **Bond number** $\mathrm{Bo}$ +or **Eötvös number** $\mathrm{Eo}$: + +$$\begin{aligned} + \boxed{ + \mathrm{Bo} + = \mathrm{Eo} + = \frac{L^2}{L_c^2} + = \frac{m g}{\alpha L} + } +\end{aligned}$$ + +The right-most side gives an alternative way of understanding $\mathrm{Bo}$: +$m$ is the mass of a cube with side $L$, such that the numerator is the weight force, +and the denominator is the tension force of the surface. +In any case, capillary action can be observed when $\mathrm{Bo \ll 1}$. + +The most famous example of capillary action is **capillary rise**, +where a liquid "climbs" upwards in a narrow vertical tube with radius $R$, +apparently defying gravity. +Assuming the liquid-air interface is a spherical cap +with constant [curvature](/know/concept/curvature/) radius $R_c$, +then we know that the liquid is at rest +when the hydrostatic pressure equals the Laplace pressure: + +$$\begin{aligned} + \rho g h + \approx \alpha \frac{2}{R_c} + = 2 \alpha \frac{\cos\theta}{R} +\end{aligned}$$ + +Where $\theta$ is the liquid-tube contact angle, +and we are neglecting variations of the height $h$ due to the curvature +(i.e. the [meniscus](/know/concept/meniscus/)). +By isolating the above equation for $h$, +we arrive at **Jurin's law**, +which predicts the height climbed by a liquid in a tube with radius $R$: + +$$\begin{aligned} + \boxed{ + h + = 2 \frac{L_c^2}{R} \cos\theta + } +\end{aligned}$$ + +Depending on $\theta$, $h$ can be negative, +i.e. the liquid might descend below the ambient level. + + +An alternative derivation of Jurin's law balances the forces instead of the pressures. +On the right, we have the gravitational force +(i.e. the energy-per-distance to lift the liquid), +and on the left, the surface tension force +(i.e. the energy-per-distance of the liquid-tube interface): + +$$\begin{aligned} + \pi R^2 \rho g h + \approx 2 \pi R (\alpha_{sg} - \alpha_{sl}) +\end{aligned}$$ + +Where $\alpha_{sg}$ and $\alpha_{sl}$ are the energy costs +of the solid-gas and solid-liquid interfaces. +Thanks to the [Young-Dupré relation](/know/concept/young-dupre-relation/), +we can rewrite this as follows: + +$$\begin{aligned} + R \rho g h + = 2 \alpha \cos\theta +\end{aligned}$$ + +Isolating this for $h$ simply yields Jurin's law again, as expected. + + + +## References +1. B. Lautrup, + *Physics of continuous matter: exotic and everyday phenomena in the macroscopic world*, 2nd edition, + CRC Press. -- cgit v1.2.3