From bd349aaace1deb21fa6d88719b7009b63aec542a Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Mon, 7 Mar 2022 12:07:23 +0100
Subject: Expand knowledge base

---
 content/know/concept/cylindrical-polar-coordinates/index.pdc | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

(limited to 'content/know/concept/cylindrical-polar-coordinates')

diff --git a/content/know/concept/cylindrical-polar-coordinates/index.pdc b/content/know/concept/cylindrical-polar-coordinates/index.pdc
index 6242b9f..0b2acd1 100644
--- a/content/know/concept/cylindrical-polar-coordinates/index.pdc
+++ b/content/know/concept/cylindrical-polar-coordinates/index.pdc
@@ -47,7 +47,7 @@ $$\begin{aligned}
 \end{aligned}$$
 
 The cylindrical polar coordinates form an orthogonal
-[curvilinear](/know/concept/curvilinear-coordinates/) system,
+[curvilinear system](/know/concept/curvilinear-coordinates/),
 whose scale factors $h_r$, $h_\varphi$ and $h_z$ we want to find.
 To do so, we calculate the differentials of the Cartesian coordinates:
 
@@ -141,7 +141,7 @@ $$\begin{aligned}
             \\
             &+ \vu{e}_\varphi \Big( \pdv{V_r}{z} - \pdv{V_z}{r} \Big)
             \\
-            &+ \frac{\vu{e}_\varphi}{r} \Big( \pdv{(r V_\varphi)}{r} - \pdv{V_r}{\varphi} \Big)
+            &+ \frac{\vu{e}_z}{r} \Big( \pdv{(r V_\varphi)}{r} - \pdv{V_r}{\varphi} \Big)
         \end{aligned}
     }
 \end{aligned}$$
-- 
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