From f7c7464e29cb19083a2488c393f3707e97248c4f Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Sat, 25 Sep 2021 10:26:44 +0200
Subject: Expand knowledge base

---
 content/know/concept/heisenberg-picture/index.pdc | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

(limited to 'content/know/concept/heisenberg-picture/index.pdc')

diff --git a/content/know/concept/heisenberg-picture/index.pdc b/content/know/concept/heisenberg-picture/index.pdc
index 9e4887d..c49169f 100644
--- a/content/know/concept/heisenberg-picture/index.pdc
+++ b/content/know/concept/heisenberg-picture/index.pdc
@@ -20,7 +20,7 @@ In the Schrödinger picture, the operators (observables) are fixed
 (as long as they do not depend on time), while the state
 $\ket{\psi_S(t)}$ changes according to the Schrödinger equation,
 which can be written using the generator of translations
-$\hat{U}(t) = \exp{} (- i t \hat{H} / \hbar)$ like so:
+$\hat{U}(t) = \exp\!(- i t \hat{H} / \hbar)$ like so:
 
 $$\begin{aligned}
     \ket{\psi_S(t)} = \hat{U}(t) \ket{\psi_S(0)}
@@ -100,7 +100,7 @@ $$\begin{aligned}
 \end{aligned}$$
 
 This equation is closer to classical mechanics than the Schrödinger picture:
-inserting the position $\hat{X}$ and momentum $\hat{P} = - i \hbar \: d/d\hat{X}$
+inserting the position $\hat{X}$ and momentum $\hat{P} = - i \hbar \: \dv*{\hat{X}}$
 gives the following Newton-style equations:
 
 $$\begin{aligned}
-- 
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