From 4780106a4f191c41d3b82ca9d1327a1c95a72055 Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Thu, 27 May 2021 20:46:01 +0200
Subject: Expand knowledge base

---
 content/know/concept/hydrostatic-pressure/index.pdc | 12 ++++++------
 1 file changed, 6 insertions(+), 6 deletions(-)

(limited to 'content/know/concept/hydrostatic-pressure')

diff --git a/content/know/concept/hydrostatic-pressure/index.pdc b/content/know/concept/hydrostatic-pressure/index.pdc
index 90e57ce..001a198 100644
--- a/content/know/concept/hydrostatic-pressure/index.pdc
+++ b/content/know/concept/hydrostatic-pressure/index.pdc
@@ -141,8 +141,10 @@ $$\begin{aligned}
 With this, the equilibrium condition is turned into the following equation:
 
 $$\begin{aligned}
-    \nabla \Phi + \frac{\nabla p}{\rho}
-    = 0
+    \boxed{
+        \nabla \Phi + \frac{\nabla p}{\rho}
+        = 0
+    }
 \end{aligned}$$
 
 In practice, the density $\rho$ of the fluid
@@ -156,7 +158,7 @@ the indefinite integral of the density:
 
 $$\begin{aligned}
     w(p)
-    = \int \frac{1}{\rho(p)} \dd{p}
+    \equiv \int \frac{1}{\rho(p)} \dd{p}
 \end{aligned}$$
 
 Using this, we can rewrite the equilibrium condition as a single gradient like so:
@@ -172,9 +174,7 @@ From this, let us now define the
 **effective gravitational potential** $\Phi^*$ as follows:
 
 $$\begin{aligned}
-    \boxed{
-        \Phi^* = \Phi + w(p)
-    }
+    \Phi^* \equiv \Phi + w(p)
 \end{aligned}$$
 
 This results in the cleanest form yet of the equilibrium condition, namely:
-- 
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