--- title: "Thermodynamic potential" firstLetter: "T" publishDate: 2021-07-07 categories: - Physics - Thermodynamics date: 2021-07-03T14:40:22+02:00 draft: false markup: pandoc --- # Thermodynamic potential **Thermodynamic potentials** are state functions whose minima or maxima represent equilibrium states of a system. Such functions are either energies (hence *potential*) or entropies. Which potential (of many) decides the equilibrium states for a given system? That depends which variables are assumed to already be in automatic equilibrium. Such variables are known as the **natural variables** of that potential. For example, if a system can freely exchange heat with its surroundings, and is consequently assumed to be at the same temperature $T = T_{\mathrm{sur}}$, then $T$ must be a natural variable. The link from natural variables to potentials is established by [thermodynamic ensembles](/know/category/thermodynamic-ensembles/). Once enough natural variables have been found, the appropriate potential can be selected from the list below. All non-natural variables can then be calculated by taking partial derivatives of the potential with respect to the natural variables. Mathematically, the potentials are related to each other by [Legendre transformation](/know/concept/legendre-transform/). ## Internal energy The **internal energy** $U$ represents the capacity to do both mechanical and non-mechanical work, and to release heat. It is simply the integral of the [fundamental thermodynamic relation](/know/concept/fundamental-thermodynamic-relation/): $$\begin{aligned} \boxed{ U(S, V, N) \equiv T S - P V + \mu N } \end{aligned}$$ It is a function of the entropy $S$, volume $V$, and particle count $N$: these are its natural variables. An infinitesimal change $\dd{U}$ is as follows: $$\begin{aligned} \boxed{ \dd{U} = T \dd{S} - P \dd{V} + \mu \dd{N} } \end{aligned}$$ The non-natural variables are temperature $T$, pressure $P$, and chemical potential $\mu$. They can be recovered by differentiating $U$ with respect to the natural variables $S$, $V$, and $N$: $$\begin{aligned} \boxed{ T = \Big( \pdv{U}{S} \Big)_{V,N} \qquad P = - \Big( \pdv{U}{V} \Big)_{S,N} \qquad \mu = \Big( \pdv{U}{N} \Big)_{S,V} } \end{aligned}$$ It is convention to write those subscripts, to help keep track of which function depends on which variables. They are meaningless; these are normal partial derivatives. ## Enthalpy The **enthalpy** $H$ of a system, in units of energy, represents its capacity to do non-mechanical work, plus its capacity to release heat. It is given by: $$\begin{aligned} \boxed{ H(S, P, N) \equiv U + P V } \end{aligned}$$ It is a function of the entropy $S$, pressure $P$, and particle count $N$: these are its natural variables. An infinitesimal change $\dd{H}$ is as follows: $$\begin{aligned} \boxed{ \dd{H} = T \dd{S} + V \dd{P} + \mu \dd{N} } \end{aligned}$$ The non-natural variables are temperature $T$, volume $V$, and chemical potential $\mu$. They can be recovered by differentiating $H$ with respect to the natural variables $S$, $P$, and $N$: $$\begin{aligned} \boxed{ T = \Big( \pdv{H}{S} \Big)_{P,N} \qquad V = \Big( \pdv{H}{P} \Big)_{S,N} \qquad \mu = \Big( \pdv{H}{N} \Big)_{S,P} } \end{aligned}$$ ## Helmholtz free energy The **Helmholtz free energy** $F$ represents the capacity of a system to do both mechanical and non-mechanical work, and is given by: $$\begin{aligned} \boxed{ F(T, V, N) \equiv U - T S } \end{aligned}$$ It depends on the temperature $T$, volume $V$, and particle count $N$: these are natural variables. An infinitesimal change $\dd{H}$ is as follows: $$\begin{aligned} \boxed{ \dd{F} = - P \dd{V} - S \dd{T} + \mu \dd{N} } \end{aligned}$$ The non-natural variables are entropy $S$, pressure $P$, and chemical potential $\mu$. They can be recovered by differentiating $F$ with respect to the natural variables $T$, $V$, and $N$: $$\begin{aligned} \boxed{ S = - \Big( \pdv{F}{T} \Big)_{V,N} \qquad P = - \Big( \pdv{F}{V} \Big)_{T,N} \qquad \mu = \Big( \pdv{F}{N} \Big)_{T,V} } \end{aligned}$$ ## Gibbs free energy The **Gibbs free energy** $G$ represents the capacity of a system to do non-mechanical work: $$\begin{aligned} \boxed{ G(T, P, N) \equiv U + P V - T S } \end{aligned}$$ It depends on the temperature $T$, pressure $P$, and particle count $N$: they are natural variables. An infinitesimal change $\dd{G}$ is as follows: $$\begin{aligned} \boxed{ \dd{G} = V \dd{P} - S \dd{T} + \mu \dd{N} } \end{aligned}$$ The non-natural variables are entropy $S$, volume $V$, and chemical potential $\mu$. These can be recovered by differentiating $G$ with respect to the natural variables $T$, $P$, and $N$: $$\begin{aligned} \boxed{ S = - \Big( \pdv{G}{T} \Big)_{P,N} \qquad V = \Big( \pdv{G}{P} \Big)_{T,N} \qquad \mu = \Big( \pdv{G}{N} \Big)_{T,P} } \end{aligned}$$ ## Landau potential The **Landau potential** or **grand potential** $\Omega$, in units of energy, represents the capacity of a system to do mechanical work, and is given by: $$\begin{aligned} \boxed{ \Omega(T, V, \mu) \equiv U - T S - \mu N } \end{aligned}$$ It depends on temperature $T$, volume $V$, and chemical potential $\mu$: these are natural variables. An infinitesimal change $\dd{\Omega}$ is as follows: $$\begin{aligned} \boxed{ \dd{\Omega} = - P \dd{V} - S \dd{T} - N \dd{\mu} } \end{aligned}$$ The non-natural variables are entropy $S$, pressure $P$, and particle count $N$. These can be recovered by differentiating $\Omega$ with respect to the natural variables $T$, $V$, and $\mu$: $$\begin{aligned} \boxed{ S = - \Big( \pdv{\Omega}{T} \Big)_{V,\mu} \qquad P = - \Big( \pdv{\Omega}{V} \Big)_{T,\mu} \qquad N = - \Big( \pdv{\Omega}{\mu} \Big)_{T,V} } \end{aligned}$$ ## Entropy The **entropy** $S$, in units of energy over temperature, is an odd duck, but nevertheless used as a thermodynamic potential. It is given by: $$\begin{aligned} \boxed{ S(U, V, N) \equiv \frac{1}{T} U + \frac{P}{T} V - \frac{\mu}{T} N } \end{aligned}$$ It depends on the internal energy $U$, volume $V$, and particle count $N$: they are natural variables. An infinitesimal change $\dd{S}$ is as follows: $$\begin{aligned} \boxed{ \dd{S} = \frac{1}{T} \dd{U} + \frac{P}{T} \dd{V} - \frac{\mu}{T} \dd{N} } \end{aligned}$$ The non-natural variables are $1/T$, $P/T$, and $\mu/T$. These can be recovered by differentiating $S$ with respect to the natural variables $U$, $V$, and $N$: $$\begin{aligned} \boxed{ \frac{1}{T} = \Big( \pdv{S}{U} \Big)_{V,N} \qquad \frac{P}{T} = \Big( \pdv{S}{V} \Big)_{U,N} \qquad \frac{\mu}{T} = - \Big( \pdv{S}{N} \Big)_{U,V} } \end{aligned}$$ ## References 1. H. Gould, J. Tobochnik, *Statistical and thermal physics*, 2nd edition, Princeton.