--- title: "Vorticity" firstLetter: "V" publishDate: 2021-04-03 categories: - Physics - Fluid mechanics - Fluid dynamics date: 2021-04-03T09:24:42+02:00 draft: false markup: pandoc --- # Vorticity In fluid mechanics, the **vorticity** $\va{\omega}$ is a measure of the local circulation in a fluid. It is defined as the curl of the flow velocity field $\va{v}$: $$\begin{aligned} \boxed{ \va{\omega} \equiv \nabla \cross \va{v} } \end{aligned}$$ Just as curves tangent to $\va{v}$ are called *streamlines*, curves tangent to $\va{\omega}$ are **vortex lines**, which are to be interpreted as the "axes" that $\va{v}$ is circulating around. The vorticity is a local quantity, and the corresponding global quantity is the **circulation** $\Gamma$, which is defined as the projection of $\va{v}$ onto a close curve $C$. Then, by Stokes' theorem: $$\begin{aligned} \boxed{ \Gamma(C, t) \equiv \oint_C \va{v} \cdot \dd{\va{l}} = \int_S \va{\omega} \cdot \dd{\va{S}} } \end{aligned}$$ ## Ideal fluids For an inviscid, incompressible fluid, consider the *Bernoulli field* $H$, which is defined as: $$\begin{aligned} H \equiv \frac{1}{2} \va{v}^2 + \Phi + \frac{p}{\rho} \end{aligned}$$ Where $\Phi$ is the gravitational potential, $p$ is the pressure, and $\rho$ is the (constant) density. We then take the gradient of this scalar field: $$\begin{aligned} \nabla H &= \frac{1}{2} \nabla \va{v}^2 + \nabla \Phi + \frac{\nabla p}{\rho} \\ &= \va{v} \cdot (\nabla \va{v}) - \Big( \!-\! \nabla \Phi - \frac{\nabla p}{\rho} \Big) \end{aligned}$$ Since $-\nabla \Phi = \va{g}$, the rightmost term is the right-hand side of the [Euler equation](/know/concept/euler-equations/). We substitute the other side of said equation, yielding: $$\begin{aligned} \nabla H &= \va{v} \cdot (\nabla \va{v}) - \frac{\mathrm{D} \va{v}}{\mathrm{D} t} = \va{v} \cdot (\nabla \va{v}) - \pdv{\va{v}}{t} - (\va{v} \cdot \nabla) \va{v} \end{aligned}$$ We isolate this equation for $\pdv*{\va{v}}{t}$, and apply a vector identity to reduce it to the following: $$\begin{aligned} \pdv{\va{v}}{t} = \va{v} \cdot (\nabla \va{v}) - (\va{v} \cdot \nabla) \va{v} - \nabla H = \va{v} \cross (\nabla \cross \va{v}) - \nabla H \end{aligned}$$ Here, the definition of the vorticity $\va{\omega}$ is clear to see, leading us to an equation of motion for $\va{v}$: $$\begin{aligned} \boxed{ \pdv{\va{v}}{t} = \va{v} \cross \va{\omega} - \nabla H } \end{aligned}$$ More about this later. Now, we take the curl of both sides of this equation, giving us: $$\begin{aligned} \nabla \cross \pdv{\va{v}}{t} = \nabla \cross (\va{v} \cross \va{\omega}) - \nabla \cross (\nabla H) \end{aligned}$$ On the left, we swap $\nabla$ with $\pdv*{t}$, and on the right, the curl of a gradient is always zero. We are thus left with the equation of motion of the vorticity $\va{\omega}$: $$\begin{aligned} \boxed{ \pdv{\va{\omega}}{t} = \nabla \cross (\va{v} \cross \va{\omega}) } \end{aligned}$$ Let us now return to the equation of motion for $\va{v}$. For *steady* flows where $\pdv*{\va{v}}{t} = 0$, in which case [Bernoulli's theorem](/know/concept/bernoullis-theorem/) applies, it reduces to: $$\begin{aligned} \nabla H = \va{v} \cross \va{\omega} \end{aligned}$$ If a fluid has $\va{\omega} = 0$ in some regions, it is known as **irrotational**. From this equation, we see that, in that case, $\nabla H = 0$, meaning that $H$ is a constant in those regions, a fact sometimes referred to as **Bernoulli's stronger theorem**. Furthermore, irrotationality $\va{\omega} = 0$ implies that $\va{v}$ is the gradient of a potential $\Psi$: $$\begin{aligned} \va{v} = \nabla \Psi \end{aligned}$$ This fact allows us to rewrite the Euler equations in a particularly simple way. Firstly, the condition of incompressibility becomes the well-known Laplace equation: $$\begin{aligned} 0 = \nabla \cdot \va{v} = \nabla^2 \Psi \end{aligned}$$ And second, the main equation of motion for $\va{v}$ states that the quantity $H + \pdv*{\Psi}{t}$ is spatially constant in the irrotational region: $$\begin{aligned} \pdv{\va{v}}{t} = \nabla \pdv{\Psi}{t} = - \nabla H \quad \implies \quad \nabla \Big( H + \pdv{\Psi}{t} \Big) = 0 \end{aligned}$$ ## References 1. B. Lautrup, *Physics of continuous matter: exotic and everyday phenomena in the macroscopic world*, 2nd edition, CRC Press.