From 1d700ab734aa9b6711eb31796beb25cb7659d8e0 Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Tue, 20 Dec 2022 20:11:25 +0100
Subject: More improvements to knowledge base

---
 source/know/concept/alfven-waves/index.md | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)

(limited to 'source/know/concept/alfven-waves')

diff --git a/source/know/concept/alfven-waves/index.md b/source/know/concept/alfven-waves/index.md
index 31576f3..0396c7a 100644
--- a/source/know/concept/alfven-waves/index.md
+++ b/source/know/concept/alfven-waves/index.md
@@ -61,12 +61,12 @@ $$\begin{aligned}
     = \frac{1}{\mu_0} \nabla \cross \vb{B}_1
 \end{aligned}$$
 
-Substituting this into the momentum equation,
+Substituting this into the above momentum equation,
 and differentiating with respect to $$t$$:
 
 $$\begin{aligned}
     \rho \pdvn{2}{\vb{u}_1}{t}
-    = \frac{1}{\mu_0} \bigg( \Big( \nabla \cross \pdv{}{\vb{B}1}{t} \Big) \cross \vb{B}_0 \bigg)
+    = \frac{1}{\mu_0} \bigg( \Big( \nabla \cross \pdv{\vb{B}_1}{t} \Big) \cross \vb{B}_0 \bigg)
 \end{aligned}$$
 
 For which we can use Faraday's law to rewrite $$\ipdv{\vb{B}_1}{t}$$,
@@ -78,7 +78,7 @@ $$\begin{aligned}
     = \nabla \cross (\vb{u}_1 \cross \vb{B}_0)
 \end{aligned}$$
 
-Inserting this into the momentum equation for $$\vb{u}_1$$
+Inserting this back into the momentum equation for $$\vb{u}_1$$
 thus yields its final form:
 
 $$\begin{aligned}
-- 
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