From a8d31faecc733fa4d63fde58ab98a5e9d11029c2 Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Sun, 2 Apr 2023 16:57:12 +0200
Subject: Improve knowledge base

---
 source/know/concept/bernstein-vazirani-algorithm/index.md | 5 +++--
 1 file changed, 3 insertions(+), 2 deletions(-)

(limited to 'source/know/concept/bernstein-vazirani-algorithm')

diff --git a/source/know/concept/bernstein-vazirani-algorithm/index.md b/source/know/concept/bernstein-vazirani-algorithm/index.md
index 5f224dc..884cca3 100644
--- a/source/know/concept/bernstein-vazirani-algorithm/index.md
+++ b/source/know/concept/bernstein-vazirani-algorithm/index.md
@@ -76,8 +76,9 @@ $$\begin{aligned}
     \frac{1}{\sqrt{2^N}} \sum_{x = 0}^{2^N - 1} (-1)^{s \cdot x} \Ket{x}
 \end{aligned}$$
 
-Then, thanks to the definition of the Hadamard transform,
-a final set of $$H$$-gates leads us to:
+Then, using the definition of the Hadamard transform
+and the fact that it is its own inverse,
+one final set of $$H$$-gates leads us to:
 
 $$\begin{aligned}
     \frac{1}{\sqrt{2^N}} \sum_{x = 0}^{2^N - 1} (-1)^{s \cdot x} \Ket{x}
-- 
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