From 6e70f28ccbd5afc1506f71f013278a9d157ef03a Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Thu, 27 Oct 2022 20:40:09 +0200
Subject: Optimize last images, add proof template, improve CSS

---
 source/know/concept/boltzmann-equation/index.md | 31 +++++++------------------
 1 file changed, 9 insertions(+), 22 deletions(-)

(limited to 'source/know/concept/boltzmann-equation/index.md')

diff --git a/source/know/concept/boltzmann-equation/index.md b/source/know/concept/boltzmann-equation/index.md
index 9ed2fd2..d2631b2 100644
--- a/source/know/concept/boltzmann-equation/index.md
+++ b/source/know/concept/boltzmann-equation/index.md
@@ -145,11 +145,8 @@ $$\begin{aligned}
     }
 \end{aligned}$$
 
-<div class="accordion">
-<input type="checkbox" id="proof-moment0"/>
-<label for="proof-moment0">Proof</label>
-<div class="hidden" markdown="1">
-<label for="proof-moment0">Proof.</label>
+
+{% include proof/start.html id="proof-moment0" -%}
 We insert $$Q = m$$ into our prototype,
 and since $$m$$ is constant, the rest is trivial:
 
@@ -159,9 +156,8 @@ $$\begin{aligned}
     \\
     &= \pdv{\rho}{t} + \nabla \cdot \big(\rho \Expval{\vb{v}}\big) - 0
 \end{aligned}$$
+{% include proof/end.html id="proof-moment0" %}
 
-</div>
-</div>
 
 If we instead choose the momentum $$Q = m \vb{v}$$,
 we find that the **first moment** of the BTE describes conservation of momentum,
@@ -174,11 +170,8 @@ $$\begin{aligned}
     }
 \end{aligned}$$
 
-<div class="accordion">
-<input type="checkbox" id="proof-moment1"/>
-<label for="proof-moment1">Proof</label>
-<div class="hidden" markdown="1">
-<label for="proof-moment1">Proof.</label>
+
+{% include proof/start.html id="proof-moment1" -%}
 We insert $$Q = m \vb{v}$$ into our prototype and recognize $$\rho$$ wherever possible:
 
 $$\begin{aligned}
@@ -220,9 +213,8 @@ $$\begin{aligned}
     0
     &= \pdv{}{t}\big(\rho \vb{V}\big) + \nabla \cdot \big(\rho \vb{V} \vb{V} + \hat{P}\big) - n \vb{F}
 \end{aligned}$$
+{% include proof/end.html id="proof-moment1" %}
 
-</div>
-</div>
 
 Finally, if we choose the kinetic energy $$Q = m |\vb{v}|^2 / 2$$,
 we find that the **second moment** gives conservation of energy,
@@ -237,11 +229,8 @@ $$\begin{aligned}
     }
 \end{aligned}$$
 
-<div class="accordion">
-<input type="checkbox" id="proof-moment2"/>
-<label for="proof-moment2">Proof</label>
-<div class="hidden" markdown="1">
-<label for="proof-moment2">Proof.</label>
+
+{% include proof/start.html id="proof-moment2" -%}
 We insert $$Q = m |\vb{v}|^2 / 2$$ into our prototype and recognize $$\rho$$ wherever possible:
 
 $$\begin{aligned}
@@ -349,9 +338,7 @@ $$\begin{aligned}
     \end{bmatrix}
     = \sum_{i=1}^{3} \sum_{j=1}^{3} \pdv{P_{ij}}{x_j} V_i
 \end{aligned}$$
-
-</div>
-</div>
+{% include proof/end.html id="proof-moment2" %}
 
 
 
-- 
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