From 6e70f28ccbd5afc1506f71f013278a9d157ef03a Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Thu, 27 Oct 2022 20:40:09 +0200
Subject: Optimize last images, add proof template, improve CSS

---
 source/know/concept/parsevals-theorem/index.md | 10 +++-------
 1 file changed, 3 insertions(+), 7 deletions(-)

(limited to 'source/know/concept/parsevals-theorem')

diff --git a/source/know/concept/parsevals-theorem/index.md b/source/know/concept/parsevals-theorem/index.md
index df90244..377f3a1 100644
--- a/source/know/concept/parsevals-theorem/index.md
+++ b/source/know/concept/parsevals-theorem/index.md
@@ -24,11 +24,8 @@ $$\begin{aligned}
     }
 \end{aligned}$$
 
-<div class="accordion">
-<input type="checkbox" id="proof-fourier"/>
-<label for="proof-fourier">Proof</label>
-<div class="hidden" markdown="1">
-<label for="proof-fourier">Proof.</label>
+
+{% include proof/start.html id="proof-fourier" -%}
 We insert the inverse FT into the defintion of the inner product:
 
 $$\begin{aligned}
@@ -68,9 +65,8 @@ $$\begin{aligned}
     &= \frac{2 \pi A^2}{|s|} \int_{-\infty}^\infty f^*(x) \: g(x) \dd{x}
     = \frac{2 \pi A^2}{|s|} \Inprod{f}{g}
 \end{aligned}$$
+{% include proof/end.html id="proof-fourier" %}
 
-</div>
-</div>
 
 For this reason, physicists like to define the Fourier transform
 with $$A\!=\!B\!=\!1 / \sqrt{2\pi}$$ and $$|s|\!=\!1$$, because then it nicely
-- 
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