From bcae81336764eb6c4cdf0f91e2fe632b625dd8b2 Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Sun, 23 Oct 2022 22:18:11 +0200
Subject: Optimize and improve naming of all images in knowledge base

---
 source/know/concept/quantum-fourier-transform/index.md | 8 ++------
 1 file changed, 2 insertions(+), 6 deletions(-)

(limited to 'source/know/concept/quantum-fourier-transform/index.md')

diff --git a/source/know/concept/quantum-fourier-transform/index.md b/source/know/concept/quantum-fourier-transform/index.md
index 113367c..1c68ad0 100644
--- a/source/know/concept/quantum-fourier-transform/index.md
+++ b/source/know/concept/quantum-fourier-transform/index.md
@@ -172,17 +172,13 @@ The quantum circuit to execute the mentioned steps is illustrated below,
 excluding the swapping part to get the right order.
 Here, $$R_m$$ means $$R_\phi$$ with $$\phi = 2 \pi / 2^m$$:
 
-<a href="qft-circuit-noswap.png">
-<img src="qft-circuit-noswap.png" style="width:100%">
-</a>
+{% include image.html file="qft-circuit-noswap.png" width="100%" alt="QFT circuit, without final swap" %}
 
 Again, note how the inputs $$\Ket{x_j}$$ and outputs $$\Ket{k_j}$$ are in the opposite order.
 The complete circuit, including the swapping at the end,
 therefore looks like this:
 
-<a href="qft-circuit-swap.png">
-<img src="qft-circuit-swap.png" style="width:85%">
-</a>
+{% include image.html file="qft-circuit-swap.png" width="85%" alt="QFT circuit, including final swap" %}
 
 For each of the $$n$$ qubits, $$\mathcal{O}(n)$$ gates are applied,
 so overall the QFT algorithm is $$\mathcal{O}(n^2)$$.
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