From bcae81336764eb6c4cdf0f91e2fe632b625dd8b2 Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Sun, 23 Oct 2022 22:18:11 +0200
Subject: Optimize and improve naming of all images in knowledge base

---
 source/know/concept/rutherford-scattering/index.md | 8 ++------
 1 file changed, 2 insertions(+), 6 deletions(-)

(limited to 'source/know/concept/rutherford-scattering/index.md')

diff --git a/source/know/concept/rutherford-scattering/index.md b/source/know/concept/rutherford-scattering/index.md
index a7375d5..6f5a21f 100644
--- a/source/know/concept/rutherford-scattering/index.md
+++ b/source/know/concept/rutherford-scattering/index.md
@@ -19,9 +19,7 @@ Let 2 be initially at rest, and 1 approach it with velocity $$\vb{v}_1$$.
 Coulomb repulsion causes 1 to deflect by an angle $$\theta$$,
 and pushes 2 away in the process:
 
-<a href="two-body.png">
-<img src="two-body.png" style="width:50%">
-</a>
+{% include image.html file="two-body-full.png" width="50%" alt="Two-body repulsive 'collision'" %}
 
 Here, $$b$$ is called the **impact parameter**.
 Intuitively, we expect $$\theta$$ to be larger for smaller $$b$$.
@@ -69,9 +67,7 @@ then by comparing $$t > 0$$ and $$t < 0$$
 we can see that $$v_x$$ is unchanged for any given $$\pm t$$,
 while $$v_y$$ simply changes sign:
 
-<a href="one-body.png">
-<img src="one-body.png" style="width:60%">
-</a>
+{% include image.html file="one-body-full.png" width="60%" alt="Equivalent one-body deflection" %}
 
 From our expression for $$\vb{r}$$,
 we can find $$\vb{v}$$ by differentiating with respect to time:
-- 
cgit v1.2.3