From bcae81336764eb6c4cdf0f91e2fe632b625dd8b2 Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Sun, 23 Oct 2022 22:18:11 +0200
Subject: Optimize and improve naming of all images in knowledge base
---
source/know/concept/step-index-fiber/index.md | 10 +++-------
1 file changed, 3 insertions(+), 7 deletions(-)
(limited to 'source/know/concept/step-index-fiber/index.md')
diff --git a/source/know/concept/step-index-fiber/index.md b/source/know/concept/step-index-fiber/index.md
index dd83334..c0c95d1 100644
--- a/source/know/concept/step-index-fiber/index.md
+++ b/source/know/concept/step-index-fiber/index.md
@@ -240,14 +240,12 @@ $$\begin{aligned}
\end{cases}
\end{aligned}$$
-
-
-
+{% include image.html file="bessel-full.png" width="100%" alt="First few solutions to Bessel's equation" %}
Looking at these solutions with our constraints for $$R_o$$ in mind,
we see that for $$\mu > 0$$ none of the solutions decay
*monotonically* to zero, so we must have $$\mu \le 0$$ in the cladding.
-Of the remaining candidates, $$\ln\!(r)$$, $$r^\ell$$ and $$I_\ell(\rho)$$ do not decay at all,
+Of the remaining candidates, $$\ln(r)$$, $$r^\ell$$ and $$I_\ell(\rho)$$ do not decay at all,
leading to the following $$R_o$$:
$$\begin{aligned}
@@ -394,9 +392,7 @@ An example graphical solution of the transcendental equation
is illustrated below for a fiber with $$V = 5$$,
where red and blue respectively denote the left and right-hand side:
-
-
-
+{% include image.html file="transcendental-full.png" width="100%" alt="Graphical solution of transcendental equation" %}
This shows that each $$\mathrm{LP}_{\ell m}$$ has an associated cut-off $$V_{\ell m}$$,
so that if $$V > V_{\ell m}$$ then $$\mathrm{LP}_{lm}$$ exists,
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