From 6e70f28ccbd5afc1506f71f013278a9d157ef03a Mon Sep 17 00:00:00 2001 From: Prefetch Date: Thu, 27 Oct 2022 20:40:09 +0200 Subject: Optimize last images, add proof template, improve CSS --- source/know/concept/superdense-coding/index.md | 63 +++----------------------- 1 file changed, 6 insertions(+), 57 deletions(-) (limited to 'source/know/concept/superdense-coding') diff --git a/source/know/concept/superdense-coding/index.md b/source/know/concept/superdense-coding/index.md index ba6e898..4338205 100644 --- a/source/know/concept/superdense-coding/index.md +++ b/source/know/concept/superdense-coding/index.md @@ -27,63 +27,12 @@ Based on the values of the two classical bits $$(a_1, a_2)$$, Alice performs the following operations on her side $$A$$ of the Bell state: - - - - - - - - - - - - - - - - - - - - - - - - - - -
- $$(a_1, a_2)$$ - - Operator - - Result -
- $$00$$ - - $$\hat{I}$$ - - $$\displaystyle \ket{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B + \Ket{1}_A \Ket{1}_B \Big)$$ -
- $$01$$ - - $$\hat{\sigma}_z$$ - - $$\displaystyle \ket{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B - \Ket{1}_A \Ket{1}_B \Big)$$ -
- $$10$$ - - $$\hat{\sigma}_x$$ - - $$\displaystyle \ket{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B + \Ket{1}_A \Ket{0}_B \Big)$$ -
- $$11$$ - - $$\hat{\sigma}_x \hat{\sigma}_z$$ - - $$\displaystyle \ket{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B - \Ket{1}_A \Ket{0}_B \Big)$$ -
+| $$(a_1, a_2)$$ | **Operator** | **Result** | +| :-: | :-: | :-: | +| $$00$$ | $$\hat{I}$$ | $$\displaystyle \ket{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B + \Ket{1}_A \Ket{1}_B \Big)$$ | +| $$01$$ | $$\hat{\sigma}_z$$ | $$\displaystyle \ket{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B - \Ket{1}_A \Ket{1}_B \Big)$$ | +| $$10$$ | $$\hat{\sigma}_x$$ | $$\displaystyle \ket{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B + \Ket{1}_A \Ket{0}_B \Big)$$ | +| $$11$$ | $$\hat{\sigma}_x \hat{\sigma}_z$$ | $$\displaystyle \ket{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B - \Ket{1}_A \Ket{0}_B \Big)$$ | Her actions affect the state on Bob's side $$B$$ due to entanglement. Alice then sends her qubit $$A$$ to Bob over the quantum channel, -- cgit v1.2.3