--- title: "Bernoulli's theorem" sort_title: "Bernoulli's theorem" date: 2021-04-02 categories: - Physics - Fluid mechanics - Fluid dynamics layout: "concept" --- For inviscid fluids, **Bernouilli's theorem** states that an increase in flow velocity $$\va{v}$$ is paired with a decrease in pressure $$p$$ and/or potential energy. Quantitatively, for an incompressible fluid with a time-independent velocity field $$\va{v}$$ (i.e. **steady flow**), Bernoulli's theorem states that the **Bernoulli head** $$H$$ is constant along every streamline: $$\begin{aligned} \boxed{ H \equiv \frac{1}{2} |\va{v}|^2 + \Phi + \frac{p}{\rho} } \end{aligned}$$ Where $$\Phi$$ is the gravitational potential, such that $$\va{g} = - \nabla \Phi$$. To prove this theorem, we take the [material derivative](/know/concept/material-derivative/) of $$H$$: $$\begin{aligned} \frac{\mathrm{D} H}{\mathrm{D} t} &= \va{v} \cdot \frac{\mathrm{D} \va{v}}{\mathrm{D} t} + \frac{\mathrm{D} \Phi}{\mathrm{D} t} + \frac{1}{\rho} \frac{\mathrm{D} p}{\mathrm{D} t} \end{aligned}$$ In the first term we insert the [Euler equation](/know/concept/euler-equations/), and in the other two we expand the derivatives: $$\begin{aligned} \frac{\mathrm{D} H}{\mathrm{D} t} &= \va{v} \cdot \Big( \va{g} - \frac{\nabla p}{\rho} \Big) + \Big( \pdv{\Phi}{t} + (\va{v} \cdot \nabla) \Phi \Big) + \frac{1}{\rho} \Big( \pdv{p}{t} + (\va{v} \cdot \nabla) p \Big) \\ &= \pdv{\Phi}{t} + \frac{1}{\rho} \pdv{p}{t} + \va{v} \cdot \big( \va{g} + \nabla \Phi \big) + \va{v} \cdot \Big( \frac{\nabla p}{\rho} - \frac{\nabla p}{\rho} \Big) \end{aligned}$$ Using the fact that $$\va{g} = - \nabla \Phi$$, we are left with the following equation: $$\begin{aligned} \frac{\mathrm{D} H}{\mathrm{D} t} &= \pdv{\Phi}{t} + \frac{1}{\rho} \pdv{p}{t} \end{aligned}$$ Assuming that the flow is steady, both derivatives vanish, leading us to the conclusion that $$H$$ is conserved along the streamline. In fact, there exists **Bernoulli's stronger theorem**, which states that $$H$$ is constant *everywhere* in regions with zero [vorticity](/know/concept/vorticity/) $$\va{\omega} = 0$$. For a proof, see the derivation of $$\va{\omega}$$'s equation of motion. ## References 1. B. Lautrup, *Physics of continuous matter: exotic and everyday phenomena in the macroscopic world*, 2nd edition, CRC Press.