--- title: "Debye length" date: 2021-10-18 categories: - Physics - Plasma physics layout: "concept" --- If a charged object is put in a plasma, it repels like charges and attracts opposite charges, leading to a **Debye sheath** around the object's surface with a net opposite charge. This has the effect of **shielding** the object's presence from the rest of the plasma. We start from [Gauss' law](/know/concept/maxwells-equations/) for the [electric field](/know/concept/electric-field/) $\vb{E}$, expressing $\vb{E}$ as the gradient of a potential $\phi$, i.e. $\vb{E} = -\nabla \phi$, and splitting the charge density into ions $n_i$ and electrons $n_e$: $$\begin{aligned} \nabla^2 \phi(\vb{r}) = - \frac{1}{\varepsilon_0} \Big( q_i n_i(\vb{r}) + q_e n_e(\vb{r}) + q_t \delta(\vb{r}) \Big) \end{aligned}$$ The last term represents a *test particle*, which will be shielded. This particle is a point charge $q_t$, whose density is simply a [Dirac delta function](/know/concept/dirac-delta-function/) $\delta(\vb{r})$, and is not included in $n_i$ or $n_e$. For a plasma in thermal equilibrium, we have the [Boltzmann relations](/know/concept/boltzmann-relation/) for the densities: $$\begin{aligned} n_i(\vb{r}) = n_{i0} \exp\!\bigg( \!-\! \frac{q_i \phi(\vb{r})}{k_B T_i} \bigg) \qquad \quad n_e(\vb{r}) = n_{e0} \exp\!\bigg( \!-\! \frac{q_e \phi(\vb{r})}{k_B T_e} \bigg) \end{aligned}$$ We assume that electrical interactions are weak compared to thermal effects, i.e. $k_B T \gg q \phi$ in both cases. Then we Taylor-expand the Boltzmann relations to first order: $$\begin{aligned} n_i(\vb{r}) \approx n_{i0} \bigg( 1 - \frac{q_i \phi(\vb{r})}{k_B T_i} \bigg) \qquad \quad n_e(\vb{r}) \approx n_{e0} \bigg( 1 - \frac{q_e \phi(\vb{r})}{k_B T_e} \bigg) \end{aligned}$$ Inserting this back into Gauss' law, we arrive at the following equation for $\phi(\vb{r})$, where we have assumed quasi-neutrality such that $q_i n_{i0} = q_e n_{e0}$: $$\begin{aligned} \nabla^2 \phi &= - \frac{1}{\varepsilon_0} \bigg( q_i n_{i0} - n_{i0} \frac{q_i^2 \phi}{k_B T_i} + q_e n_{e0} - n_{e0} \frac{q_e^2 \phi}{k_B T_e} + q_t \delta(\vb{r}) \bigg) \\ &= \bigg( \frac{n_{i0} q_i^2}{\varepsilon_0 k_B T_i} + \frac{n_{e0} q_e^2}{\varepsilon_0 k_B T_e} \bigg) \phi - \frac{q_t}{\varepsilon_0} \delta(\vb{r}) \end{aligned}$$ We now define the **ion** and **electron Debye lengths** $\lambda_{Di}$ and $\lambda_{De}$ as follows: $$\begin{aligned} \boxed{ \frac{1}{\lambda_{Di}^2} \equiv \frac{n_{i0} q_i^2}{\varepsilon_0 k_B T_i} } \qquad \quad \boxed{ \frac{1}{\lambda_{De}^2} \equiv \frac{n_{e0} q_e^2}{\varepsilon_0 k_B T_e} } \end{aligned}$$ And then the **total Debye length** $\lambda_D$ is defined as the sum of their inverses, and gives the rough thickness of the Debye sheath: $$\begin{aligned} \boxed{ \frac{1}{\lambda_D^2} \equiv \frac{1}{\lambda_{Di}^2} + \frac{1}{\lambda_{De}^2} = \frac{n_{i0} q_i^2 T_e + n_{e0} q_e^2 T_i}{\varepsilon_0 k_B T_i T_e} } \end{aligned}$$ With this, the equation can be put in the form below, suggesting exponential decay: $$\begin{aligned} \nabla^2 \phi(\vb{r}) &= \frac{1}{\lambda_D^2} \phi(\vb{r}) - \frac{q_t}{\varepsilon_0} \delta(\vb{r}) \end{aligned}$$ This has the following solution, known as the **Yukawa potential**, which decays exponentially, representing the plasma's **self-shielding** over a characteristic distance $\lambda_D$: $$\begin{aligned} \boxed{ \phi(r) = \frac{q_t}{4 \pi \varepsilon_0 r} \exp\!\Big( \!-\!\frac{r}{\lambda_D} \Big) } \end{aligned}$$ Note that $r$ is a scalar, i.e. the potential depends only on the radial distance to $q_t$. This treatment only makes sense if the plasma is sufficiently dense, such that there is a large number of particles in a sphere with radius $\lambda_D$. This corresponds to a large [Coulomb logarithm](/know/concept/coulomb-logarithm/) $\ln\!(\Lambda)$: $$\begin{aligned} 1 \ll \frac{4 \pi}{3} n_0 \lambda_D^3 = \frac{2}{9} \Lambda \end{aligned}$$ The name *Yukawa potential* originates from particle physics, but can in general be used to refer to any potential (electric or energetic) of the following form: $$\begin{aligned} V(r) = \frac{A}{r} \exp(-B r) \end{aligned}$$ Where $A$ and $B$ are scaling constants that depend on the problem at hand. ## References 1. P.M. Bellan, *Fundamentals of plasma physics*, 1st edition, Cambridge. 2. M. Salewski, A.H. Nielsen, *Plasma physics: lecture notes*, 2021, unpublished.