--- title: "Electric field" date: 2021-07-12 categories: - Physics - Electromagnetism layout: "concept" --- The **electric field** $\vb{E}$ is a vector field that describes electric effects, and is defined as the field that correctly predicts the [Lorentz force](/know/concept/lorentz-force/) on a particle with electric charge $q$: $$\begin{aligned} \vb{F} = q \vb{E} \end{aligned}$$ This definition implies that the direction of $\vb{E}$ is from positive to negative charges, since opposite charges attracts and like charges repel. If two opposite point charges with magnitude $q$ are observed from far away, they can be treated as a single object called a **dipole**, which has an **electric dipole moment** $\vb{p}$ defined like so, where $\vb{d}$ is the vector going from the negative to the positive charge (opposite direction of $\vb{E}$): $$\begin{aligned} \vb{p} = q \vb{d} \end{aligned}$$ Alternatively, for consistency with [magnetic fields](/know/concept/magnetic-field/), $\vb{p}$ can be defined from the aligning torque $\vb{\tau}$ experienced by the dipole when placed in an $\vb{E}$-field. In other words, $\vb{p}$ satisfies: $$\begin{aligned} \vb{\tau} = \vb{p} \times \vb{E} \end{aligned}$$ Where $\vb{p}$ has units of $\mathrm{C m}$. The **polarization density** $\vb{P}$ is defined from $\vb{p}$, and roughly speaking represents the moments per unit volume: $$\begin{aligned} \vb{P} \equiv \dv{\vb{p}}{V} \:\:\iff\:\: \vb{p} = \int_V \vb{P} \dd{V} \end{aligned}$$ If $\vb{P}$ has the same magnitude and direction throughout the body, then this becomes $\vb{p} = \vb{P} V$, where $V$ is the volume. Therefore, $\vb{P}$ has units of $\mathrm{C / m^2}$. A nonzero $\vb{P}$ complicates things, since it contributes to the field and hence modifies $\vb{E}$. We thus define the "free" **displacement field** $\vb{D}$ from the "bound" field $\vb{P}$ and the "net" field $\vb{E}$: $$\begin{aligned} \vb{D} \equiv \varepsilon_0 \vb{E} + \vb{P} \:\:\iff\:\: \vb{E} = \frac{1}{\varepsilon_0} (\vb{D} - \vb{P}) \end{aligned}$$ Where the **electric permittivity of free space** $\varepsilon_0$ is a known constant. It is important to point out some inconsistencies here: $\vb{D}$ and $\vb{P}$ contain a factor of $\varepsilon_0$, and therefore measure **flux density**, while $\vb{E}$ does not contain $\varepsilon_0$, and thus measures **field intensity**. Note that this convention is the opposite of the magnetic analogues $\vb{B}$, $\vb{H}$ and $\vb{M}$, and that $\vb{M}$ has the opposite sign of $\vb{P}$. The polarization $\vb{P}$ is a function of $\vb{E}$. In addition to the inherent polarity of the material $\vb{P}_0$ (zero in most cases), there is a (possibly nonlinear) response to the applied $\vb{E}$-field: $$\begin{aligned} \vb{P} = \vb{P}_0 + \varepsilon_0 \chi_e^{(1)} \vb{E} + \varepsilon_0 \chi_e^{(2)} |\vb{E}| \: \vb{E} + \varepsilon_0 \chi_e^{(3)} |\vb{E}|^2 \: \vb{E} + ... \end{aligned}$$ Where the $\chi_e^{(n)}$ are the **electric susceptibilities** of the medium. For simplicity, we often assume that only the $n\!=\!1$ term is nonzero, which is the linear response to $\vb{E}$. In that case, we define the **absolute permittivity** $\varepsilon$ so that: $$\begin{aligned} \vb{D} = \varepsilon_0 \vb{E} + \vb{P} = \varepsilon_0 \vb{E} + \varepsilon_0 \chi_e^{(1)} \vb{E} = \varepsilon_0 \varepsilon_r \vb{E} = \varepsilon \vb{E} \end{aligned}$$ I.e. $\varepsilon \equiv \varepsilon_r \varepsilon_0$, where $\varepsilon_r \equiv 1 + \chi_e^{(1)}$ is the [**dielectric function**](/know/concept/dielectric-function/) or **relative permittivity**, whose calculation is of great interest in physics. In reality, a material cannot respond instantly to $\vb{E}$, meaning that $\chi_e^{(1)}$ is a function of time, and that $\vb{P}$ is the convolution of $\chi_e^{(1)}(t)$ and $\vb{E}(t)$: $$\begin{aligned} \vb{P}(t) = \varepsilon_0 \big(\chi_e^{(1)} * \vb{E}\big)(t) = \varepsilon_0 \int_{-\infty}^\infty \chi_e^{(1)}(t - \tau) \: \vb{E}(\tau) \:d\tau \end{aligned}$$ Note that this definition requires $\chi_e^{(1)}(t) = 0$ for $t < 0$ in order to ensure causality, which leads to the [Kramers-Kronig relations](/know/concept/kramers-kronig-relations/).