--- title: "Laguerre polynomials" sort_title: "Laguerre polynomials" date: 2021-09-08 categories: - Mathematics layout: "concept" --- The **Laguerre polynomials** are a set of useful functions that arise in physics. They are the non-singular eigenfunctions $$u(x)$$ of **Laguerre's equation**, with the corresponding eigenvalues $$n$$ being non-negative integers: $$\begin{aligned} \boxed{ x u'' + (1 - x) u' + n u = 0 } \end{aligned}$$ The $$n$$th-order Laguerre polynomial $$L_n(x)$$ is given in the form of a *Rodrigues' formula* by: $$\begin{aligned} L_n(x) &= \frac{1}{n!} \exp(x) \dvn{n}{}{x}\big(x^n \exp(-x)\big) \\ &= \frac{1}{n!} \Big( \dv{}{x}- 1 \Big)^n x^n \end{aligned}$$ The first couple of Laguerre polynomials $$L_n(x)$$ are therefore as follows: $$\begin{gathered} L_0(x) = 1 \qquad \quad L_1(x) = 1 - x \qquad \quad L_2(x) = \frac{1}{2} (x^2 - 4 x + 2) \end{gathered}$$ Based on Laguerre's equation, **Laguerre's generalized equation** is as follows, with an arbitrary real (but usually integer) parameter $$\alpha$$, and $$n$$ still a non-negative integer: $$\begin{aligned} \boxed{ x u'' + (\alpha + 1 - x) u' + n u = 0 } \end{aligned}$$ Its solutions, denoted by $$L_n^\alpha(x)$$, are the **generalized** or **associated Laguerre polynomials**, which also have a Rodrigues' formula. Note that if $$\alpha = 0$$ then $$L_n^\alpha = L_n$$: $$\begin{aligned} L_n^\alpha(x) &= \frac{1}{n!} x^{-\alpha} \exp(x) \dvn{n}{}{x}\big( x^{n + \alpha} \exp(-x) \big) \\ &= \frac{x^{-\alpha}}{n!} \Big( \dv{}{x}- 1 \Big)^n x^{n + \alpha} \end{aligned}$$ The first couple of associated Laguerre polynomials $$L_n^\alpha(x)$$ are therefore as follows: $$\begin{aligned} L_0^\alpha(x) = 1 \qquad L_1^\alpha(x) = \alpha + 1 - x \qquad L_2^\alpha(x) = \frac{1}{2} (x^2 - 2 \alpha x - 4 x + \alpha^2 + 3 \alpha + 2) \end{aligned}$$ And then more $$L_n^\alpha$$ can be computed quickly using the following recurrence relation: $$\begin{aligned} \boxed{ L_{n + 1}^\alpha(x) = \frac{(\alpha + 2 n + 1 - x) L_n^\alpha(x) - (\alpha + n) L_{n - 1}^\alpha(x)}{n + 1} } \end{aligned}$$ The derivatives are also straightforward to calculate using the following relation: $$\begin{aligned} \boxed{ \dvn{k}{}{x}L_n^\alpha(x) = (-1)^k L_{n - k}^{\alpha + k}(x) } \end{aligned}$$ Noteworthy is that these polynomials (both normal and associated) are all mutually orthogonal for $$x \in [0, \infty[$$, with respect to the weight function $$w(x) \equiv x^\alpha \exp(-x)$$: $$\begin{aligned} \boxed{ \Inprod{L_m^\alpha}{w L_n^\alpha} = \int_0^\infty L_m^\alpha(x) \: L_n^\alpha(x) \: w(x) \dd{x} = \frac{\Gamma(n + \alpha + 1)}{n!} \delta_{nm} } \end{aligned}$$ Where $$\delta_{nm}$$ is the Kronecker delta. Moreover, they form a basis in the [Hilbert space](/know/concept/hilbert-space/) of all functions $$f(x)$$ for which $$\Inprod{f}{w f}$$ is finite. Any such $$f$$ can thus be expanded as follows: $$\begin{aligned} \boxed{ f(x) = \sum_{n = 0}^\infty a_n L_n^\alpha(x) = \sum_{n = 0}^\infty \frac{\Inprod{L_n}{w f}}{\Inprod{L_n}{w L_n}} L_n^\alpha(x) } \end{aligned}$$ Finally, the $$L_n^\alpha(x)$$ are related to the [Hermite polynomials](/know/concept/hermite-polynomials/) $$H_n(x)$$ like so: $$\begin{aligned} H_{2n(x)} &= (-1)^n 2^{2n} n! \: L_n^{-1/2}(x^2) \\ H_{2n + 1(x)} &= (-1)^n 2^{2n + 1} n! \: L_n^{1/2}(x^2) \end{aligned}$$