From ff039a8d60e81c771dab31c72d349ef9560c8537 Mon Sep 17 00:00:00 2001
From: Prefetch
Date: Wed, 24 Feb 2021 09:54:20 +0100
Subject: Final commit for archival

---
 latex/know/concept/hilbert-space/source.md | 8 ++++----
 1 file changed, 4 insertions(+), 4 deletions(-)

(limited to 'latex/know/concept/hilbert-space')

diff --git a/latex/know/concept/hilbert-space/source.md b/latex/know/concept/hilbert-space/source.md
index 3f6ceb5..780fc0a 100644
--- a/latex/know/concept/hilbert-space/source.md
+++ b/latex/know/concept/hilbert-space/source.md
@@ -89,8 +89,8 @@ $\braket{U}{V} = 0$. If in addition to being orthogonal, $|U| = 1$ and
 $|V| = 1$, then $U$ and $V$ are known as **orthonormal** vectors.
 
 Orthonormality is desirable for basis vectors, so if they are
-not already orthonormal, it is common to manually derive a new
-orthonormal basis from them using e.g. the [Gram-Schmidt method](/know/concept/gram-schmidt-method).
+not already like that, it is common to manually turn them into a new
+orthonormal basis using e.g. the [Gram-Schmidt method](/know/concept/gram-schmidt-method).
 
 As for the implementation of the inner product, it is given by:
 
@@ -171,8 +171,8 @@ $$\begin{aligned}
     = \int_a^b \braket{x}{\xi} f(\xi) \dd{\xi}
 \end{aligned}$$
 
-For the latter integral to turn into $f(x)$, it is plain to see that
-$\braket{x}{\xi}$ must be a [Dirac delta function](/know/concept/dirac-delta-function/),
+Since we want the latter integral to reduce to $f(x)$, it is plain to see that
+$\braket{x}{\xi}$ can only be a [Dirac delta function](/know/concept/dirac-delta-function/),
 i.e $\braket{x}{\xi} = \delta(x - \xi)$:
 
 $$\begin{aligned}
-- 
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