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-rw-r--r--source/know/concept/runge-kutta-method/index.md86
1 files changed, 43 insertions, 43 deletions
diff --git a/source/know/concept/runge-kutta-method/index.md b/source/know/concept/runge-kutta-method/index.md
index 270cb91..4c3dacf 100644
--- a/source/know/concept/runge-kutta-method/index.md
+++ b/source/know/concept/runge-kutta-method/index.md
@@ -10,16 +10,16 @@ layout: "concept"
A **Runge-Kutta method** (RKM) is a popular approach
to numerically solving systems of ordinary differential equations.
-Let $\vb{x}(t)$ be the vector we want to find,
-governed by $\vb{f}(t, \vb{x})$:
+Let $$\vb{x}(t)$$ be the vector we want to find,
+governed by $$\vb{f}(t, \vb{x})$$:
$$\begin{aligned}
\vb{x}'(t)
= \vb{f}\big(t, \vb{x}(t)\big)
\end{aligned}$$
-Like in all numerical methods, the $t$-axis is split into discrete steps.
-If a step has size $h$, then as long as $h$ is small enough,
+Like in all numerical methods, the $$t$$-axis is split into discrete steps.
+If a step has size $$h$$, then as long as $$h$$ is small enough,
we can make the following approximation:
$$\begin{aligned}
@@ -31,9 +31,9 @@ $$\begin{aligned}
&\approx \vb{f}\big(t \!+\! a h,\, \vb{x}(t) \!+\! a h \vb{x}'(t) \big)
\end{aligned}$$
-For sufficiently small $h$,
+For sufficiently small $$h$$,
higher-order derivates can also be included,
-albeit still at $t \!+\! a h$:
+albeit still at $$t \!+\! a h$$:
$$\begin{aligned}
\vb{x}'(t) + a h \vb{x}''(t) + b h^2 \vb{x}'''(t)
@@ -43,8 +43,8 @@ $$\begin{aligned}
Although these approximations might seem innocent,
they actually make it quite complicated to determine the error order of a given RKM.
-Now, consider a Taylor expansion around the current $t$,
-truncated at a chosen order $n$:
+Now, consider a Taylor expansion around the current $$t$$,
+truncated at a chosen order $$n$$:
$$\begin{aligned}
\vb{x}(t \!+\! h)
@@ -54,7 +54,7 @@ $$\begin{aligned}
\end{aligned}$$
We are free to split the terms as follows,
-choosing real factors $\omega_{mj}$ subject to $\sum_{j} \omega_{mj} = 1$:
+choosing real factors $$\omega_{mj}$$ subject to $$\sum_{j} \omega_{mj} = 1$$:
$$\begin{aligned}
\vb{x}(t \!+\! h)
@@ -63,9 +63,9 @@ $$\begin{aligned}
+ \:...\, + \frac{h^{n-1}}{n!} \sum_{j = 1}^{N_n} \omega_{nj} \, \vb{x}^{(n)} \bigg]
\end{aligned}$$
-Where the integers $N_1,...,N_n$ are also free to choose,
+Where the integers $$N_1,...,N_n$$ are also free to choose,
but for reasons that will become clear later,
-the most general choice for an RKM is $N_1 = n$, $N_n = 1$, and:
+the most general choice for an RKM is $$N_1 = n$$, $$N_n = 1$$, and:
$$\begin{aligned}
N_{n-1}
@@ -82,7 +82,7 @@ $$\begin{aligned}
= N_3 \!+\! n \!-\! 1
\end{aligned}$$
-In other words, $N_{n-m}$ is the $m$th triangular number.
+In other words, $$N_{n-m}$$ is the $$m$$th triangular number.
This is not so important,
since this is not a practical way to describe RKMs,
but it is helpful to understand how they work.
@@ -90,11 +90,11 @@ but it is helpful to understand how they work.
## Example derivation
-For example, let us truncate at $n = 3$,
-such that $N_1 = 3$, $N_2 = 3$ and $N_3 = 1$.
+For example, let us truncate at $$n = 3$$,
+such that $$N_1 = 3$$, $$N_2 = 3$$ and $$N_3 = 1$$.
The following derivation is very general,
-except it requires all $\alpha_j \neq 0$.
-Renaming $\omega_{mj}$, we start from:
+except it requires all $$\alpha_j \neq 0$$.
+Renaming $$\omega_{mj}$$, we start from:
$$\begin{aligned}
\vb{x}(t \!+\! h)
@@ -108,7 +108,7 @@ $$\begin{aligned}
\end{aligned}$$
As discussed earlier, the parenthesized expressions
-can be approximately rewritten with $\vb{f}$:
+can be approximately rewritten with $$\vb{f}$$:
$$\begin{aligned}
\vb{x}(t \!+\! h)
@@ -131,7 +131,7 @@ $$\begin{aligned}
\end{aligned}$$
Here, we can see an opportunity to save some computational time
-by reusing an evaluation of $\vb{f}$.
+by reusing an evaluation of $$\vb{f}$$.
Technically, this is optional, but it would be madness not to,
so we choose:
@@ -140,8 +140,8 @@ $$\begin{aligned}
= \frac{\gamma_3}{3 \beta_{32}}
\end{aligned}$$
-Such that the next step of $\vb{x}$'s numerical solution is as follows,
-recalling that $\sum_{j} \alpha_j = 1$:
+Such that the next step of $$\vb{x}$$'s numerical solution is as follows,
+recalling that $$\sum_{j} \alpha_j = 1$$:
$$\begin{aligned}
\boxed{
@@ -150,9 +150,9 @@ $$\begin{aligned}
}
\end{aligned}$$
-Where $\vb{k}_1$, $\vb{k}_2$ and $\vb{k}_3$ are different estimates
-of the average slope $\vb{x}'$ between $t$ and $t \!+\! h$,
-whose weighted average is used to make the $t$-step.
+Where $$\vb{k}_1$$, $$\vb{k}_2$$ and $$\vb{k}_3$$ are different estimates
+of the average slope $$\vb{x}'$$ between $$t$$ and $$t \!+\! h$$,
+whose weighted average is used to make the $$t$$-step.
They are given by:
$$\begin{aligned}
@@ -172,7 +172,7 @@ $$\begin{aligned}
}
\end{aligned}$$
-Despite the contraints on $\alpha_j$ and $\beta_j$,
+Despite the contraints on $$\alpha_j$$ and $$\beta_j$$,
there is an enormous freedom of choice here,
all leading to valid RKMs, although not necessarily good ones.
@@ -180,9 +180,9 @@ all leading to valid RKMs, although not necessarily good ones.
## General form
A more practical description goes as follows:
-in an $s$-stage RKM, a weighted average is taken
-of up to $s$ slope estimates $\vb{k}_j$ with weights $b_j$.
-Let $\sum_{j} b_j = 1$, then:
+in an $$s$$-stage RKM, a weighted average is taken
+of up to $$s$$ slope estimates $$\vb{k}_j$$ with weights $$b_j$$.
+Let $$\sum_{j} b_j = 1$$, then:
$$\begin{aligned}
\boxed{
@@ -191,7 +191,7 @@ $$\begin{aligned}
}
\end{aligned}$$
-Where the estimates $\vb{k}_1, ..., \vb{k}_s$
+Where the estimates $$\vb{k}_1, ..., \vb{k}_s$$
depend on each other, and are calculated one by one as:
$$\begin{aligned}
@@ -201,8 +201,8 @@ $$\begin{aligned}
}
\end{aligned}$$
-With $c_1 = 1$ and $\sum_{j = 1} a_{mj} = c_m$.
-Writing this out for the first few $m$, the pattern is clear:
+With $$c_1 = 1$$ and $$\sum_{j = 1} a_{mj} = c_m$$.
+Writing this out for the first few $$m$$, the pattern is clear:
$$\begin{aligned}
\vb{k}_1
@@ -233,26 +233,26 @@ $$\begin{aligned}
\end{array}
\end{aligned}$$
-Each RKM has an **order** $p$,
-such that the global truncation error is $\mathcal{O}(h^p)$,
+Each RKM has an **order** $$p$$,
+such that the global truncation error is $$\mathcal{O}(h^p)$$,
i.e. the accumulated difference between the numerical
-and the exact solutions is proportional to $h^p$.
+and the exact solutions is proportional to $$h^p$$.
-The surprise is that $p$ need not be equal to the Taylor expansion order $n$,
-nor the stage count $s$.
-Typically, $s = n$ for computational efficiency, but $s \ge n$ is possible in theory.
+The surprise is that $$p$$ need not be equal to the Taylor expansion order $$n$$,
+nor the stage count $$s$$.
+Typically, $$s = n$$ for computational efficiency, but $$s \ge n$$ is possible in theory.
-The order $p$ of a given RKM is determined by
+The order $$p$$ of a given RKM is determined by
a complicated set of equations on the coefficients,
-and the lowest possible $s$ for a desired $p$
+and the lowest possible $$s$$ for a desired $$p$$
is in fact only partially known.
-For $p \le 4$ the bound is $s \ge p$,
-whereas for $p \ge 5$ the only proven bound is $s \ge p \!+\! 1$,
-but for $p \ge 7$ no such efficient methods have been found so far.
+For $$p \le 4$$ the bound is $$s \ge p$$,
+whereas for $$p \ge 5$$ the only proven bound is $$s \ge p \!+\! 1$$,
+but for $$p \ge 7$$ no such efficient methods have been found so far.
If you need an RKM with a certain order, look it up.
-There exist many efficient methods for $p \le 4$ where $s = p$,
-and although less popular, higher $p$ are also available.
+There exist many efficient methods for $$p \le 4$$ where $$s = p$$,
+and although less popular, higher $$p$$ are also available.