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-rw-r--r--source/know/concept/time-dependent-perturbation-theory/index.md64
1 files changed, 32 insertions, 32 deletions
diff --git a/source/know/concept/time-dependent-perturbation-theory/index.md b/source/know/concept/time-dependent-perturbation-theory/index.md
index a1c1173..d39e321 100644
--- a/source/know/concept/time-dependent-perturbation-theory/index.md
+++ b/source/know/concept/time-dependent-perturbation-theory/index.md
@@ -14,24 +14,24 @@ with time-varying perturbations to the Schrödinger equation.
This is in contrast to [time-independent perturbation theory](/know/concept/time-independent-perturbation-theory/),
where the perturbation is stationary.
-Let $\hat{H}_0$ be the base time-independent
-Hamiltonian, and $\hat{H}_1$ be a time-varying perturbation, with
-"bookkeeping" parameter $\lambda$:
+Let $$\hat{H}_0$$ be the base time-independent
+Hamiltonian, and $$\hat{H}_1$$ be a time-varying perturbation, with
+"bookkeeping" parameter $$\lambda$$:
$$\begin{aligned}
\hat{H}(t) = \hat{H}_0 + \lambda \hat{H}_1(t)
\end{aligned}$$
We assume that the unperturbed time-independent problem
-$\hat{H}_0 \Ket{n} = E_n \Ket{n}$ has already been solved, such that the
+$$\hat{H}_0 \Ket{n} = E_n \Ket{n}$$ has already been solved, such that the
full solution is:
$$\begin{aligned}
\Ket{\Psi_0(t)} = \sum_{n} c_n \Ket{n} \exp(- i E_n t / \hbar)
\end{aligned}$$
-Since these $\Ket{n}$ form a complete basis, the perturbed wave function
-can be written in the same form, but with time-dependent coefficients $c_n(t)$:
+Since these $$\Ket{n}$$ form a complete basis, the perturbed wave function
+can be written in the same form, but with time-dependent coefficients $$c_n(t)$$:
$$\begin{aligned}
\Ket{\Psi(t)} = \sum_{n} c_n(t) \Ket{n} \exp(- i E_n t / \hbar)
@@ -50,7 +50,7 @@ $$\begin{aligned}
&= \sum_{n} \Big( \lambda c_n \hat{H}_1 \Ket{n} - i \hbar \dv{c_n}{t} \Ket{n} \Big) \exp(- i E_n t / \hbar)
\end{aligned}$$
-We then take the inner product with an arbitrary stationary basis state $\Ket{m}$:
+We then take the inner product with an arbitrary stationary basis state $$\Ket{m}$$:
$$\begin{aligned}
0
@@ -65,7 +65,7 @@ $$\begin{aligned}
\end{aligned}$$
We divide by the left-hand exponential and define
-$\omega_{mn} \equiv (E_m - E_n) / \hbar$ to get:
+$$\omega_{mn} \equiv (E_m - E_n) / \hbar$$ to get:
$$\begin{aligned}
\boxed{
@@ -75,7 +75,7 @@ $$\begin{aligned}
\end{aligned}$$
So far, we have not invoked any approximation,
-so we can analytically find $c_n(t)$ for some simple systems.
+so we can analytically find $$c_n(t)$$ for some simple systems.
Furthermore, it is useful to write this equation in integral form instead:
$$\begin{aligned}
@@ -84,14 +84,14 @@ $$\begin{aligned}
\end{aligned}$$
If this cannot be solved exactly, we must approximate it. We expand
-$c_m(t)$ in the usual way, with the initial condition $c_m^{(j)}(0) = 0$
-for $j > 0$:
+$$c_m(t)$$ in the usual way, with the initial condition $$c_m^{(j)}(0) = 0$$
+for $$j > 0$$:
$$\begin{aligned}
c_m(t) = c_m^{(0)} + \lambda c_m^{(1)}(t) + \lambda^2 c_m^{(2)}(t) + ...
\end{aligned}$$
-We then insert this into the integral and collect the non-zero orders of $\lambda$:
+We then insert this into the integral and collect the non-zero orders of $$\lambda$$:
$$\begin{aligned}
c_m^{(1)}(t)
@@ -106,9 +106,9 @@ $$\begin{aligned}
\int_0^t c_n^{(2)}(\tau) \matrixel{m}{\hat{H}_1(\tau)}{n} \exp(i \omega_{mn} \tau) \dd{\tau}
\end{aligned}$$
-And so forth. The pattern here is clear: we can calculate the $(j\!+\!1)$th
-correction using only our previous result for the $j$th correction.
-We cannot go any further than this without considering a specific perturbation $\hat{H}_1(t)$.
+And so forth. The pattern here is clear: we can calculate the $$(j\!+\!1)$$th
+correction using only our previous result for the $$j$$th correction.
+We cannot go any further than this without considering a specific perturbation $$\hat{H}_1(t)$$.
## Sinusoidal perturbation
@@ -117,7 +117,7 @@ Arguably the most important perturbation
is a sinusoidally-varying potential, which represents
e.g. incoming electromagnetic waves,
or an AC voltage being applied to the system.
-In this case, $\hat{H}_1$ has the following form:
+In this case, $$\hat{H}_1$$ has the following form:
$$\begin{aligned}
\hat{H}_1(\vec{r}, t)
@@ -125,7 +125,7 @@ $$\begin{aligned}
= \frac{1}{2 i} V(\vec{r}) \: \big( \exp(i \omega t) - \exp(-i \omega t) \big)
\end{aligned}$$
-We abbreviate $V_{mn} = \matrixel{m}{V}{n}$,
+We abbreviate $$V_{mn} = \matrixel{m}{V}{n}$$,
and take the first-order correction formula:
$$\begin{aligned}
@@ -138,9 +138,9 @@ $$\begin{aligned}
+ \frac{\exp\!\big(i t (\omega_{mn} \!-\! \omega) \big) - 1}{\omega_{mn} - \omega} \bigg)
\end{aligned}$$
-For simplicity, we let the system start in a known state $\Ket{a}$,
-such that $c_n^{(0)} = \delta_{na}$,
-and we assume that the driving frequency is close to resonance $\omega \approx \omega_{ma}$,
+For simplicity, we let the system start in a known state $$\Ket{a}$$,
+such that $$c_n^{(0)} = \delta_{na}$$,
+and we assume that the driving frequency is close to resonance $$\omega \approx \omega_{ma}$$,
such that the second term dominates the first, which can then be neglected.
We thus get:
@@ -158,8 +158,8 @@ $$\begin{aligned}
\end{aligned}$$
Taking the norm squared yields the **transition probability**:
-the probability that a particle that started in state $\Ket{a}$
-will be found in $\Ket{m}$ at time $t$:
+the probability that a particle that started in state $$\Ket{a}$$
+will be found in $$\Ket{m}$$ at time $$t$$:
$$\begin{aligned}
\boxed{
@@ -169,22 +169,22 @@ $$\begin{aligned}
}
\end{aligned}$$
-The result would be the same if $\hat{H}_1 \equiv V \cos(\omega t)$.
-However, if instead $\hat{H}_1 \equiv V \exp(- i \omega t)$,
-the result is larger by a factor of $4$,
+The result would be the same if $$\hat{H}_1 \equiv V \cos(\omega t)$$.
+However, if instead $$\hat{H}_1 \equiv V \exp(- i \omega t)$$,
+the result is larger by a factor of $$4$$,
which can cause confusion when comparing literature.
-In any case, the probability oscillates as a function of $t$
-with period $T = 2 \pi / (\omega_{ma} \!-\! \omega)$,
-so after one period the particle is back in $\Ket{a}$,
-and after $T/2$ the particle is in $\Ket{b}$.
+In any case, the probability oscillates as a function of $$t$$
+with period $$T = 2 \pi / (\omega_{ma} \!-\! \omega)$$,
+so after one period the particle is back in $$\Ket{a}$$,
+and after $$T/2$$ the particle is in $$\Ket{b}$$.
See [Rabi oscillation](/know/concept/rabi-oscillation/)
for a more accurate treatment of this "flopping" behaviour.
-However, when regarded as a function of $\omega$,
+However, when regarded as a function of $$\omega$$,
the probability takes the form of
-a sinc-function centred around $(\omega_{ma} \!-\! \omega)$,
-so it is highest for transitions with energy $\hbar \omega = E_m \!-\! E_a$.
+a sinc-function centred around $$(\omega_{ma} \!-\! \omega)$$,
+so it is highest for transitions with energy $$\hbar \omega = E_m \!-\! E_a$$.
Also note that the sinc-distribution becomes narrower over time,
which roughly means that it takes some time