The Lorentz force is an empirical force used to define
the electric fieldE
and magnetic fieldB.
For a particle with charge q moving with velocity u,
the Lorentz force F is given by:
F=q(E+u×B)
Uniform electric field
Consider the simple case of an electric field E
that is uniform in all of space.
In the absence of a magnetic field B=0
and any other forces,
Newton’s second law states:
F=mdtdu=qE
This is straightforward to integrate in time,
for a given initial velocity vector u0:
u(t)=mqEt+u0
And then the particle’s position x(t)
is found be integrating once more,
with x(0)=x0:
x(t)=2mqEt2+u0t+x0
In summary, unsurprisingly, a uniform electric field E
accelerates the particle with a constant force F=qE.
Note that the direction depends on the sign of q.
Uniform magnetic field
Consider the simple case of a uniform magnetic field
B=(0,0,B) in the z-direction,
without an electric field E=0.
If there are no other forces,
Newton’s second law states:
F=mdtdu=qu×B
Evaluating the cross product yields
three coupled equations for the components of u:
dtdux=mqBuydtduy=−mqBuxdtduz=0
Differentiating the first equation with respect to t,
and substituting duy/dt from the second,
we arrive at the following harmonic oscillator:
dt2d2ux=−ωc2ux
Where we have defined the cyclotron frequencyωc as follows,
which may be negative:
ωc≡mqB
Suppose we choose our initial conditions so that
the solution for ux(t) is given by:
ux(t)=u⊥cos(ωct)
Where u⊥≡ux2+uy2 is the constant total transverse velocity.
Then uy(t) is found to be:
This means that the particle moves in a circle,
in a direction determined by the sign of ωc.
Integrating the velocity yields the position,
where we refer to the integration constants xgc and ygc
as the guiding center, around which the particle orbits or gyrates:
The radius of this orbit is known as the Larmor radius or gyroradiusrL, given by:
rL≡∣ωc∣u⊥=∣q∣Bmu⊥
Finally, it is easy to integrate the equation
for the z-axis velocity uz, which is conserved:
z(t)=zgc=uzt+z0
In conclusion, the particle’s motion parallel to B
is not affected by the magnetic field,
while its motion perpendicular to B
is circular around an imaginary guiding center.
The end result is that particles follow a helical path
when moving through a uniform magnetic field:
x(t)=ωcu⊥sin(ωct)cos(ωct)0+xgc(t)
Where xgc(t)≡(xgc,ygc,zgc)
is the position of the guiding center.
For a detailed look at how B and E
can affect the guiding center’s motion,
see guiding center theory.
References
F.F. Chen,
Introduction to plasma physics and controlled fusion,
3rd edition, Springer.