Categories: Physics, Plasma physics.

# Spitzer resistivity

If an electric field with magnitude $$E$$ is applied to the plasma, the electrons experience a Lorentz force $$q_e E$$ (we neglect the ions due to their mass), where $$q_e$$ is the electron charge.

However, collisions slow them down while they travel through the plasma., This can be modelled as a drag force $$f_{ei} m_e v_e$$, where $$f_{ei}$$ is the electron-ion collision frequency (we neglect $$f_{ee}$$ since all electrons are moving together), $$m_e$$ is their mass, and $$v_e$$ their typical velocity relative to the ions in the background. Balancing the two forces yields the following relation:

\begin{aligned} q_e E = f_{ei} m_e v_e \end{aligned}

Using that the current density $$J = q_e n_e v_e$$, we can rearrange this like so:

\begin{aligned} E = f_{ei} m_e \frac{J}{n_e q_e^2} = \frac{m_e f_{ei}}{n_e q_e^2} J = \eta J \end{aligned}

This is Ohm’s law, where $$\eta$$ is the resistivity. From our derivation of the Coulomb logarithm $$\ln\!(\Lambda)$$, we estimate $$f_{ei}$$ to be as follows, where $$n_i$$ is the ion density, $$\sigma$$ is the collision cross-section, and $$\mu$$ is the reduced mass of the electron-ion system:

\begin{aligned} f_{ei} = n_i \sigma v_e = \frac{1}{2 \pi} \Big( \frac{q_e q_i}{\varepsilon_0 \mu} \Big)^2 \frac{n_i}{v_e^3} \ln\!(\Lambda) \approx \frac{1}{2 \pi} \frac{Z q_e^4}{\varepsilon_0^2 m_e^2} \frac{n_e}{v_e^3} \ln\!(\Lambda) \end{aligned}

Where we used that $$\mu \approx m_e$$, and $$q_i = -Z q_e$$ for some ionization $$Z$$, and as a result $$n_e \approx Z n_i$$ due to the plasma’s quasi-neutrality. Beware: authors disagree about the constant factors in $$f_{ei}$$; recall that it was derived from fairly rough estimates. This article follows Bellan.

Inserting this expression for $$f_{ei}$$ into the so-called Spitzer resistivity $$\eta$$ then yields:

\begin{aligned} \boxed{ \eta = \frac{m_e f_{ei}}{n_e q_e^2} = \frac{1}{2 \pi} \frac{Z q_e^2}{\varepsilon_0^2 m_e} \frac{1}{v_e^3} \ln\!(\Lambda) } \end{aligned}

A reasonable estimate for the typical velocity $$v_e$$ at thermal equilibrium is as follows, where $$k_B$$ is Boltzmann’s constant, and $$T_e$$ is the electron temperature:

\begin{aligned} \frac{1}{2} m_e v_e^2 = \frac{3}{2} k_B T_e \quad \implies \quad v_e = \sqrt{\frac{3 k_B T_e}{m_e}} \end{aligned}

Other choices exist, see e.g. the Maxwell-Boltzmann distribution, but always $$v_e \propto \sqrt{T_e/m_e}$$. Inserting this $$v_e$$ into $$\eta$$ then gives:

\begin{aligned} \eta = \frac{1}{6 \pi \sqrt{3}} \frac{Z q_e^2 \sqrt{m_e}}{\varepsilon_0^2 (k_B T_e)^{3/2}} \ln\!(\Lambda) \end{aligned}

1. P.M. Bellan, Fundamentals of plasma physics, 1st edition, Cambridge.
2. M. Salewski, A.H. Nielsen, Plasma physics: lecture notes, 2021, unpublished.

© Marcus R.A. Newman, a.k.a. "Prefetch". Available under CC BY-SA 4.0.