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author | Prefetch | 2022-12-31 22:21:39 +0100 |
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committer | Prefetch | 2022-12-31 22:21:39 +0100 |
commit | 68615a9ad2c942254135cffb00cf25a84a3b1356 (patch) | |
tree | 1ed3131f673207b2ef0bdaee3ee98bb68d6640ca /09/main.py |
Initial commit
Diffstat (limited to '09/main.py')
-rwxr-xr-x | 09/main.py | 60 |
1 files changed, 60 insertions, 0 deletions
diff --git a/09/main.py b/09/main.py new file mode 100755 index 0000000..d082678 --- /dev/null +++ b/09/main.py @@ -0,0 +1,60 @@ +#!/usr/bin/python + +from itertools import permutations + + + +def parse_input(lines): + edges = {} + + for line in lines: + words = line.split() + x = words[0] + y = words[2] + d = int(words[4]) + + if x not in edges: + edges[x] = {} + if y not in edges: + edges[y] = {} + + edges[x][y] = d + edges[y][x] = d + + return edges + + + +def solve_partn(partn, lines): + edges = parse_input(lines) + nodes = list(edges.keys()) + + # This is simply the famous travelling salesman problem, + # so exhaustively trying all routes is the only solution. + routes = permutations(nodes) + totals = [] + for r in routes: + t = 0 + for i in range(len(r) - 1): + t += edges[r[i]][r[i + 1]] + totals.append(t) + + if partn == 1: + return min(totals) + else: # partn == 2 + return max(totals) + + + +def main(): + # Read distances (graph edges) from input text file + with open("input.txt", "r") as f: + lines = f.read().splitlines() + + print("Part 1 solution:", solve_partn(1, lines)) # 207 for me + print("Part 2 solution:", solve_partn(2, lines)) # 804 for me + + + +if __name__ == "__main__": + main() |