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author | Prefetch | 2021-04-09 20:44:44 +0200 |
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committer | Prefetch | 2021-04-09 20:44:44 +0200 |
commit | 45af77f068aaa57c052cd861412d53beecbe5e3b (patch) | |
tree | d3cbd058679bdeb800f6e25afedecbbc8810dffc /content/know/concept/cavitation | |
parent | 966048bd3594eac4d3398992c8ad3143e290303b (diff) |
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diff --git a/content/know/concept/cavitation/index.pdc b/content/know/concept/cavitation/index.pdc new file mode 100644 index 0000000..8f6b0c4 --- /dev/null +++ b/content/know/concept/cavitation/index.pdc @@ -0,0 +1,119 @@ +--- +title: "Cavitation" +firstLetter: "C" +publishDate: 2021-04-09 +categories: +- Physics +- Fluid mechanics +- Fluid dynamics + +date: 2021-04-06T19:03:36+02:00 +draft: false +markup: pandoc +--- + +# Cavitation + +In a liquid, **cavitation** is the spontaneous appearance of bubbles, +occurring when the pressure in a part of the liquid drops +below its vapour pressure, e.g. due to the fast movements. +When such a bubble is subjected to a higher pressure +by the surrounding liquid, it quickly implodes. + +To model this case, we use the simple form of +the [Rayleigh-Plesset equation](/know/concept/rayleigh-plesset-equation/) +for an inviscid liquid without surface tension. +Note that the RP equation assumes incompressibility. + +We assume that the whole liquid is at a constant pressure $p_\infty$, +and the bubble is empty, such that the interface pressure $P = 0$, +meaning $\Delta p = - p_\infty$. +At first, the radius is stationary $R'(0) = 0$, +and given by a constant $R(0) = a$. +The simple Rayleigh-Plesset equation is then: + +$$\begin{aligned} + R \dv[2]{R}{t} + \frac{3}{2} \bigg( \dv{R}{t} \bigg)^2 + = - \frac{p_\infty}{\rho} +\end{aligned}$$ + +To solve it, we multiply both sides by $R^2 R'$ +and rewrite it in the following way: + +$$\begin{aligned} + - 2 \frac{p_\infty}{\rho} R^2 R' + &= 2 R^3 R' R'' + 3 R^2 (R')^3 + \\ + - \frac{2 p_\infty}{3 \rho} \dv{t} \Big( R^3 \Big) + &= \dv{t} \Big( R^3 (R')^2 \Big) +\end{aligned}$$ + +It is then straightforward to integrate both sides +with respect to time $\tau$, from $0$ to $t$: + +$$\begin{aligned} + - \frac{2 p_\infty}{3 \rho} \int_0^t \dv{\tau} \Big( R^3 \Big) \dd{\tau} + &= \int_0^t \dv{\tau} \Big( R^3 (R')^2 \Big) \dd{\tau} + \\ + - \frac{2 p_\infty}{3 \rho} \Big[ R^3 \Big]_0^t + &= \Big[ R^3 (R')^2 \Big]_0^t + \\ + - \frac{2 p_\infty}{3 \rho} \Big( R^3(t) - a^3 \Big) + &= \Big( R^3(t) \: \big(R'(t)\big)^2 \Big) +\end{aligned}$$ + +Rearranging this equation yields the following expression +for the derivative $R'$: + +$$\begin{aligned} + (R')^2 + = \frac{2 p_\infty}{3 \rho} \Big( \frac{a^3}{R^3} - 1 \Big) +\end{aligned}$$ + +This equation is nasty to integrate. +The trick is to invert $R(t)$ into $t(R)$, +and, because we are only interested in collapse, +we just need to consider the case $R' < 0$. +The time of a given radius $R$ is then as follows, +where we are using slightly sloppy notation: + +$$\begin{aligned} + t + = \int_0^t \dd{\tau} + = - \int_{a}^{R} \frac{\dd{R}}{R'} + = \int_{R}^{a} \frac{\dd{R}}{R'} +\end{aligned}$$ + +The minus comes from the constraint that $R' < 0$, but $t \ge 0$. +We insert the expression for $R'$: + +$$\begin{aligned} + t + = \sqrt{\frac{3 \rho}{2 p_\infty}} \int_{R}^{a} \Bigg( \sqrt{ \frac{a^3}{R^3} - 1 } \Bigg)^{-1} \dd{R} + = \sqrt{\frac{3 \rho a^2}{2 p_\infty}} \int_{R/a}^{1} \frac{1}{\sqrt{x^{-3} - 1}} \dd{x} +\end{aligned}$$ + +This integral needs to be looked up, +and involves the hypergeometric function ${}_2 F_1$. +However, we only care about *collapse*, which is when $R = 0$. +The time $t_0$ at which this occurs is: + +$$\begin{aligned} + t_0 + = \sqrt{\frac{3 \rho a^2}{2 p_\infty}} \sqrt{\frac{3 \pi}{2}} \frac{\Gamma(5/6)}{\Gamma(1/3)} + \approx \sqrt{\frac{3 \rho a^2}{2 p_\infty}} 0.915 \:\mathrm{s} +\end{aligned}$$ + +With our assumptions, a bubble will always collapse. +However, unsurprisingly, reality turns out to be more complicated: +as $R \to 0$, the interface velocity $R' \to \infty$. +By looking at the derivation of the Rayleigh-Plesset equation, +it can be shown that the pressure just outside the bubble diverges due to $R'$. +This drastically changes the liquid's properties, and breaks our assumptions. + + + +## References +1. B. Lautrup, + *Physics of continuous matter: exotic and everyday phenomena in the macroscopic world*, 2nd edition, + CRC Press. |