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-rw-r--r--content/know/concept/boltzmann-relation/index.pdc8
1 files changed, 4 insertions, 4 deletions
diff --git a/content/know/concept/boltzmann-relation/index.pdc b/content/know/concept/boltzmann-relation/index.pdc
index ddaa22f..b892745 100644
--- a/content/know/concept/boltzmann-relation/index.pdc
+++ b/content/know/concept/boltzmann-relation/index.pdc
@@ -39,16 +39,16 @@ $$\begin{aligned}
= - k_B T_e \nabla n_e
\end{aligned}$$
-At equilibrium, we demand that $\vb{f}_e = \vb{f}_p$,
+At equilibrium, we demand that $\vb{f}_e = - \vb{f}_p$,
and isolate this equation for $\nabla n_e$, yielding:
$$\begin{aligned}
k_B T_e \nabla n_e
- = q_e n_e \nabla \phi
+ = - q_e n_e \nabla \phi
\quad \implies \quad
\nabla n_e
- = \frac{q_e \nabla \phi}{k_B T_e} n_e
- = \nabla \bigg( \frac{q_e \phi}{k_B T_e} \bigg) n_e
+ = - \frac{q_e \nabla \phi}{k_B T_e} n_e
+ = - \nabla \bigg( \frac{q_e \phi}{k_B T_e} \bigg) n_e
\end{aligned}$$
This equation is straightforward to integrate,