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-rw-r--r--content/know/concept/hydrostatic-pressure/index.pdc12
1 files changed, 6 insertions, 6 deletions
diff --git a/content/know/concept/hydrostatic-pressure/index.pdc b/content/know/concept/hydrostatic-pressure/index.pdc
index 90e57ce..001a198 100644
--- a/content/know/concept/hydrostatic-pressure/index.pdc
+++ b/content/know/concept/hydrostatic-pressure/index.pdc
@@ -141,8 +141,10 @@ $$\begin{aligned}
With this, the equilibrium condition is turned into the following equation:
$$\begin{aligned}
- \nabla \Phi + \frac{\nabla p}{\rho}
- = 0
+ \boxed{
+ \nabla \Phi + \frac{\nabla p}{\rho}
+ = 0
+ }
\end{aligned}$$
In practice, the density $\rho$ of the fluid
@@ -156,7 +158,7 @@ the indefinite integral of the density:
$$\begin{aligned}
w(p)
- = \int \frac{1}{\rho(p)} \dd{p}
+ \equiv \int \frac{1}{\rho(p)} \dd{p}
\end{aligned}$$
Using this, we can rewrite the equilibrium condition as a single gradient like so:
@@ -172,9 +174,7 @@ From this, let us now define the
**effective gravitational potential** $\Phi^*$ as follows:
$$\begin{aligned}
- \boxed{
- \Phi^* = \Phi + w(p)
- }
+ \Phi^* \equiv \Phi + w(p)
\end{aligned}$$
This results in the cleanest form yet of the equilibrium condition, namely: