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Diffstat (limited to 'content/know/concept/shors-algorithm')
| -rw-r--r-- | content/know/concept/shors-algorithm/index.pdc | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/content/know/concept/shors-algorithm/index.pdc b/content/know/concept/shors-algorithm/index.pdc index 0700408..3e3c05a 100644 --- a/content/know/concept/shors-algorithm/index.pdc +++ b/content/know/concept/shors-algorithm/index.pdc @@ -243,7 +243,7 @@ which is $\mathcal{O}(q^2 (\log{q}) \log{\log{q}})$ and therefore worse than the QFT, yielding a total complexity of $\mathcal{O}(q^2 (\log{q})^2 \log{\log{q}})$. -OK, but what does $s$ have to do factorizing integers? +OK, but what does $s$ have to do with factorizing integers? Well, recall that $f$ is given by: $$\begin{aligned} |