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Diffstat (limited to 'content/know/concept/superdense-coding/index.pdc')
| -rw-r--r-- | content/know/concept/superdense-coding/index.pdc | 33 |
1 files changed, 27 insertions, 6 deletions
diff --git a/content/know/concept/superdense-coding/index.pdc b/content/know/concept/superdense-coding/index.pdc index e50be2b..1a9337c 100644 --- a/content/know/concept/superdense-coding/index.pdc +++ b/content/know/concept/superdense-coding/index.pdc @@ -32,12 +32,33 @@ Based on the values of the two classical bits $(a_1, a_2)$, Alice performs the following operations on her side $A$ of the Bell state: -| $(a_1, a_2)$ | Operator $\qquad$ | Result | -|:--:|:--|:---------| -| $00$ | $\hat{I}$ | $\ket*{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{0}_B + \ket{1}_A \ket{1}_B \Big)$ | -| $01$ | $\hat{\sigma}_z$ | $\ket*{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{0}_B - \ket{1}_A \ket{1}_B \Big)$ | -| $10$ | $\hat{\sigma}_x$ | $\ket*{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{1}_B + \ket{1}_A \ket{0}_B \Big)$ | -| $11$ | $\hat{\sigma}_x \hat{\sigma}_z$ | $\ket*{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{1}_B - \ket{1}_A \ket{0}_B \Big)$ | +<table style="width:70%;margin:auto;text-align:center;"> + <tr> + <th>$(a_1, a_2)$</th> + <th>Operator</th> + <th>Result</th> + </tr> + <tr> + <td>$00$</td> + <td>$\hat{I}$</td> + <td>$\ket*{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{0}_B + \ket{1}_A \ket{1}_B \Big)$</td> + </tr> + <tr> + <td>$01$</td> + <td>$\hat{\sigma}_z$</td> + <td>$\ket*{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{0}_B - \ket{1}_A \ket{1}_B \Big)$</td> + </tr> + <tr> + <td>$10$</td> + <td>$\hat{\sigma}_x$</td> + <td>$\ket*{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{1}_B + \ket{1}_A \ket{0}_B \Big)$</td> + </tr> + <tr> + <td>$11$</td> + <td>$\hat{\sigma}_x \hat{\sigma}_z$</td> + <td>$\ket*{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{1}_B - \ket{1}_A \ket{0}_B \Big)$</td> + </tr> +</table> Her actions affect the state on Bob's side $B$ due to entanglement. Alice then sends her qubit $A$ to Bob over the quantum channel, |