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---
title: "Euler equations"
firstLetter: "E"
publishDate: 2021-03-31
categories:
- Physics
- Fluid mechanics
- Fluid dynamics
date: 2021-03-31T19:04:17+02:00
draft: false
markup: pandoc
---
# Euler equations
The **Euler equations** are a system of partial differential equations
that govern the movement of **ideal fluids**,
i.e. fluids without viscosity.
There exist several forms, depending on
the surrounding assumptions about the fluid.
## Incompressible fluid
In a fluid moving according to the velocity vield $\va{v}(\va{r}, t)$,
the acceleration felt by a particle is given by
the **material acceleration field** $\va{w}(\va{r}, t)$,
which is the [material derivative](/know/concept/material-derivative/) of $\va{v}$:
$$\begin{aligned}
\va{w}
\equiv \frac{\mathrm{D} \va{v}}{\mathrm{D} t}
= \pdv{\va{v}}{t} + (\va{v} \cdot \nabla) \va{v}
\end{aligned}$$
This infinitesimal particle obeys Newton's second law,
which can be written as follows:
$$\begin{aligned}
\va{w} \dd{m}
= \va{w} \rho \dd{V}
= \va{f^*} \dd{V}
\end{aligned}$$
Where $\dd{m}$ and $\dd{V}$ are the particle's mass volume,
and $\rho$ is the fluid density, which we assume, in this case, to be constant in space and time.
Then the **effective force density** $\va{f^*}$ represents the net force-per-particle.
By dividing the law by $\dd{V}$, we find:
$$\begin{aligned}
\rho \va{w}
= \va{f^*}
\end{aligned}$$
Next, we want to find another expression for $\va{f^*}$.
We know that the overall force $\va{F}$ on an arbitrary volume $V$ of the fluid
is the sum of the gravity body force $\va{F}_g$,
and the pressure contact force $\va{F}_p$ on the enclosing surface $S$.
Using the divergence theorem, we then find:
$$\begin{aligned}
\va{F}
= \va{F}_g + \va{F}_p
= \int_V \rho \va{g} \dd{V} - \oint_S p \dd{\va{S}}
= \int_V (\rho \va{g} - \nabla p) \dd{V}
= \int_V \va{f^*} \dd{V}
\end{aligned}$$
Where $p(\va{r}, t)$ is the pressure field,
and $\va{g}(\va{r}, t)$ is the gravitational acceleration field.
Combining this with Newton's law, we find the following equation for the force density:
$$\begin{aligned}
\va{f^*}
= \rho \va{w}
= \rho \va{g} - \nabla p
\end{aligned}$$
Dividing this by $\rho$,
we get the first of the system of Euler equations:
$$\begin{aligned}
\boxed{
\va{w}
= \frac{\mathrm{D} \va{v}}{\mathrm{D} t}
= \va{g} - \frac{\nabla p}{\rho}
}
\end{aligned}$$
The last ingredient is **incompressibility**:
the same volume must simultaneously
be flowing in and out of an arbitrary enclosure $S$.
Then, by the divergence theorem:
$$\begin{aligned}
0
= \oint_S \va{v} \cdot \dd{\va{S}}
= \int_V \nabla \cdot \va{v} \dd{V}
\end{aligned}$$
Since $S$ and $V$ are arbitrary,
the integrand must vanish by itself everywhere:
$$\begin{aligned}
\boxed{
\nabla \cdot \va{v} = 0
}
\end{aligned}$$
Combining this with the equation for $\va{w}$,
we get a system of two coupled differential equations:
these are the Euler equations for an incompressible fluid
with spatially uniform density $\rho$:
$$\begin{aligned}
\boxed{
\frac{\mathrm{D} \va{v}}{\mathrm{D} t}
= \va{g} - \frac{\nabla p}{\rho}
\qquad \quad
\nabla \cdot \va{v}
= 0
}
\end{aligned}$$
The above form is straightforward to generalize to incompressible fluids
with non-uniform spatial densities $\rho(\va{r}, t)$.
In other words, these fluids are "lumpy" (variable density),
but the size of their lumps does not change (incompressibility).
To update the equations, we demand conservation of mass:
the mass evolution of a volume $V$
is equal to the mass flow through its boundary $S$.
Applying the divergence theorem again:
$$\begin{aligned}
0
= \dv{t} \int_V \rho \dd{V} + \oint_S \rho \va{v} \cdot \dd{\va{S}}
= \int_V \dv{\rho}{t} + \nabla \cdot (\rho \va{v}) \dd{V}
\end{aligned}$$
Since $V$ is arbitrary, the integrand must be zero.
This leads to the following **continuity equation**,
to which we apply a vector identity:
$$\begin{aligned}
0
= \dv{\rho}{t} + \nabla \cdot (\rho \va{v})
= \dv{\rho}{t} + (\va{v} \cdot \nabla) \rho + \rho (\nabla \cdot \va{v})
\end{aligned}$$
Thanks to incompressibility, the last term disappears,
leaving us with a material derivative:
$$\begin{aligned}
\boxed{
0
= \frac{\mathrm{D} \rho}{\mathrm{D} t}
= \dv{\rho}{t} + (\va{v} \cdot \nabla) \rho
}
\end{aligned}$$
Putting everything together, Euler's system of equations
now takes the following form:
$$\begin{aligned}
\boxed{
\frac{\mathrm{D} \va{v}}{\mathrm{D} t}
= \va{g} - \frac{\nabla p}{\rho}
\qquad
\nabla \cdot \va{v}
= 0
\qquad
\frac{\mathrm{D} \rho}{\mathrm{D} t}
= 0
}
\end{aligned}$$
Usually, however, when discussing incompressible fluids,
$\rho$ is assumed to be spatially uniform,
in which case the latter equation is trivially satisfied.
## References
1. B. Lautrup,
*Physics of continuous matter: exotic and everyday phenomena in the macroscopic world*, 2nd edition,
CRC Press.
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