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authorPrefetch2026-09-14 18:11:38 +0200
committerPrefetch2026-09-14 18:11:38 +0200
commitcc391ce3b9867d88d124e147931d33be34e756fc (patch)
treed719cf6ad60f559fcc0c2042907a2c4d8cd62977 /source/know/concept/bernoullis-theorem
parent5cacf4ffaf3a9621ab536195f6469f98a420f054 (diff)
Improve knowledge base
Diffstat (limited to 'source/know/concept/bernoullis-theorem')
-rw-r--r--source/know/concept/bernoullis-theorem/index.md29
1 files changed, 7 insertions, 22 deletions
diff --git a/source/know/concept/bernoullis-theorem/index.md b/source/know/concept/bernoullis-theorem/index.md
index 867c443..2795f22 100644
--- a/source/know/concept/bernoullis-theorem/index.md
+++ b/source/know/concept/bernoullis-theorem/index.md
@@ -12,36 +12,21 @@ layout: "concept"
For inviscid fluids, **Bernouilli's theorem** states
that an increase in flow velocity $$\va{v}$$ is paired
with a decrease in pressure $$p$$ and/or potential energy.
-For a qualitative argument, look no further than
-one of the [Euler equations](/know/concept/euler-equations/),
-with a [material derivative](/know/concept/material-derivative/):
-
-$$\begin{aligned}
- \frac{\mathrm{D} \va{v}}{\mathrm{D} t}
- = \pdv{\va{v}}{t} + (\va{v} \cdot \nabla) \va{v}
- = \va{g} - \frac{\nabla p}{\rho}
-\end{aligned}$$
-
-Assuming that $$\va{v}$$ is constant in $$t$$,
-it becomes clear that a higher $$\va{v}$$ requires a lower $$p$$.
-
-
-## Simple form
-
-For an incompressible fluid
+Quantitatively, for an incompressible fluid
with a time-independent velocity field $$\va{v}$$ (i.e. **steady flow**),
-Bernoulli's theorem formally states that the
-**Bernoulli head** $$H$$ is constant along a streamline:
+Bernoulli's theorem states that
+the **Bernoulli head** $$H$$ is constant along every streamline:
$$\begin{aligned}
\boxed{
H
- = \frac{1}{2} \va{v}^2 + \Phi + \frac{p}{\rho}
+ \equiv \frac{1}{2} |\va{v}|^2 + \Phi + \frac{p}{\rho}
}
\end{aligned}$$
Where $$\Phi$$ is the gravitational potential, such that $$\va{g} = - \nabla \Phi$$.
-To prove this theorem, we take the material derivative of $$H$$:
+To prove this theorem, we take the
+[material derivative](/know/concept/material-derivative/) of $$H$$:
$$\begin{aligned}
\frac{\mathrm{D} H}{\mathrm{D} t}
@@ -50,7 +35,7 @@ $$\begin{aligned}
+ \frac{1}{\rho} \frac{\mathrm{D} p}{\mathrm{D} t}
\end{aligned}$$
-In the first term we insert the Euler equation,
+In the first term we insert the [Euler equation](/know/concept/euler-equations/),
and in the other two we expand the derivatives:
$$\begin{aligned}