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authorPrefetch2026-09-05 21:55:33 +0200
committerPrefetch2026-09-05 21:55:33 +0200
commit5cacf4ffaf3a9621ab536195f6469f98a420f054 (patch)
tree317b734468a287c50d2403fdfafa45434f538150 /source/know/concept/heisenberg-picture
parent29b49508a751649310173e592b63415dbf563a2a (diff)
Improve knowledge baseHEADmaster
Diffstat (limited to 'source/know/concept/heisenberg-picture')
-rw-r--r--source/know/concept/heisenberg-picture/index.md3
1 files changed, 1 insertions, 2 deletions
diff --git a/source/know/concept/heisenberg-picture/index.md b/source/know/concept/heisenberg-picture/index.md
index 54bf397..3ffe29a 100644
--- a/source/know/concept/heisenberg-picture/index.md
+++ b/source/know/concept/heisenberg-picture/index.md
@@ -118,7 +118,7 @@ This result is arguably more intuitive than the Schrödinger picture,
because it allows us to think about observables (i.e. operators) in a more classical way.
For example, inserting the position $$\hat{X}$$
and momentum $$\hat{P} = - i \hbar \: \idv{}{\hat{X}}$$
-gives the following Newton-style relations:
+gives the following Newton-style relations (details omitted):
$$\begin{aligned}
\dv{\hat{X}}{t}
@@ -130,7 +130,6 @@ $$\begin{aligned}
= - \dv{V(\hat{X})}{\hat{X}}
\end{aligned}$$
-Where the commutators have been treated as known.
These equations would not be valid in the Schrödinger picture,
unless we took their expectation value
to get [Ehrenfest's theorem](/know/concept/ehrenfests-theorem/).