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authorPrefetch2023-01-01 16:40:56 +0100
committerPrefetch2023-01-01 17:02:29 +0100
commitb1a9b1b9b2f04efd6dc39bd2a02c544d34d1259c (patch)
tree1fd87919deee17e58f8ad19c09abd54bd4a70886 /source/know/concept/self-energy
parent1d700ab734aa9b6711eb31796beb25cb7659d8e0 (diff)
Change license, add Makefile, add image caching control
Diffstat (limited to 'source/know/concept/self-energy')
-rw-r--r--source/know/concept/self-energy/index.md9
1 files changed, 6 insertions, 3 deletions
diff --git a/source/know/concept/self-energy/index.md b/source/know/concept/self-energy/index.md
index f233466..4120011 100644
--- a/source/know/concept/self-energy/index.md
+++ b/source/know/concept/self-energy/index.md
@@ -204,7 +204,8 @@ that exactly $$2^m m!$$ diagrams at each order are topologically equivalent,
so we are left with non-equivalent diagrams only.
Let $$G(b,a) = G_{ba}$$:
-{% include image.html file="expansion.png" width="90%" alt="Full expansion of G in Feynman diagrams" %}
+{% include image.html file="expansion.png" width="90%"
+ alt="Full expansion of G in Feynman diagrams" %}
A **reducible diagram** is a Feynman diagram
that can be cut in two valid diagrams
@@ -215,7 +216,8 @@ At last, we define the **self-energy** $$\Sigma(y,x)$$
as the sum of all irreducible terms in $$G(b,a)$$,
after removing the two external lines from/to $$a$$ and $$b$$:
-{% include image.html file="definition.png" width="90%" alt="Definition of self-energy" %}
+{% include image.html file="definition.png" width="90%"
+ alt="Definition of the self-energy" %}
Despite its appearance, the self-energy has the semantics of a line,
so it has two endpoints over which to integrate if necessary.
@@ -234,7 +236,8 @@ Thanks to this recursive structure,
you can convince youself that $$G(b,a)$$ obeys
a [Dyson equation](/know/concept/dyson-equation/) involving $$\Sigma(y, x)$$:
-{% include image.html file="dyson.png" width="95%" alt="Dyson equation in Feynman diagrams" %}
+{% include image.html file="dyson.png" width="95%"
+ alt="Dyson equation in Feynman diagrams" %}
This makes sense: in the "normal" Dyson equation
we have a one-body perturbation instead of $$\Sigma$$,