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authorPrefetch2022-12-20 20:11:25 +0100
committerPrefetch2022-12-20 20:11:25 +0100
commit1d700ab734aa9b6711eb31796beb25cb7659d8e0 (patch)
treeefdd26b83be1d350d7c6c01baef11a54fa2c5b36 /source/know/concept/self-phase-modulation
parenta39bb3b8aab1aeb4fceaedc54c756703819776c3 (diff)
More improvements to knowledge base
Diffstat (limited to 'source/know/concept/self-phase-modulation')
-rw-r--r--source/know/concept/self-phase-modulation/index.md15
1 files changed, 9 insertions, 6 deletions
diff --git a/source/know/concept/self-phase-modulation/index.md b/source/know/concept/self-phase-modulation/index.md
index 48ea20b..931e10b 100644
--- a/source/know/concept/self-phase-modulation/index.md
+++ b/source/know/concept/self-phase-modulation/index.md
@@ -12,8 +12,8 @@ layout: "concept"
In fiber optics, **self-phase modulation** (SPM) is a nonlinear effect
that gradually broadens pulses' spectra.
-Unlike dispersion, SPM does create new frequencies: in the $$\omega$$-domain,
-the pulse steadily spreads out with a distinctive "accordion" peak.
+Unlike dispersion, SPM creates frequencies: in the $$\omega$$-domain,
+the pulse steadily spreads out in a distinctive "accordion" shape.
Lower frequencies are created at the front of the
pulse and higher ones at the back, giving S-shaped spectrograms.
@@ -32,22 +32,25 @@ For any arbitrary input pulse $$A_0(t) = A(0, t)$$,
we arrive at the following analytical solution:
$$\begin{aligned}
- A(z,t) = A_0 \exp\!\big( i \gamma |A_0|^2 z\big)
+ A(z,t)
+ = A_0 \exp\!\big( i \gamma |A_0|^2 z\big)
\end{aligned}$$
The intensity $$|A|^2$$ in the time domain is thus unchanged,
and only its phase is modified.
-It is also clear that the largest phase increase occurs at the peak of the pulse,
+Clearly, the largest phase shift increase occurs at the peak,
where the intensity is $$P_0$$.
To quantify this, it is useful to define the **nonlinear length** $$L_N$$,
which gives the distance after which the phase of the
peak has increased by exactly 1 radian:
$$\begin{aligned}
- \gamma P_0 L_N = 1
+ \gamma P_0 L_N
+ = 1
\qquad \implies \qquad
\boxed{
- L_N = \frac{1}{\gamma P_0}
+ L_N
+ \equiv \frac{1}{\gamma P_0}
}
\end{aligned}$$