Migrate from 'jekyll-katex' to 'kramdown-math-sskatex'

1 files changed, 62 insertions, 32 deletions

diff --git a/source/know/concept/superdense-coding/index.md b/source/know/concept/superdense-coding/index.md
index 5c1e4ca..ba6e898 100644
--- a/source/know/concept/superdense-coding/index.md
+++ b/source/know/concept/superdense-coding/index.md
@@ -20,48 +20,78 @@ She could send a qubit, which has a larger state space than a classical bit,
 but it can only be measured once, thereby yielding only one bit of data.
 
 However, they are already sharing an entangled pair of qubits
-in the [Bell state](/know/concept/bell-state/) $\ket{\Phi^{+}}_{AB}$,
-where $A$ and $B$ are qubits belonging to Alice and Bob, respectively.
+in the [Bell state](/know/concept/bell-state/) $$\ket{\Phi^{+}}_{AB}$$,
+where $$A$$ and $$B$$ are qubits belonging to Alice and Bob, respectively.
 
-Based on the values of the two classical bits $(a_1, a_2)$,
-Alice performs the following operations on her side $A$
+Based on the values of the two classical bits $$(a_1, a_2)$$,
+Alice performs the following operations on her side $$A$$
 of the Bell state:
 
 <table style="width:70%;margin:auto;text-align:center;">
-    <tr>
-        <th>$(a_1, a_2)$</th>
-        <th>Operator</th>
-        <th>Result</th>
-    </tr>
-    <tr>
-        <td>$00$</td>
-        <td>$\hat{I}$</td>
-        <td>$\ket{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B + \Ket{1}_A \Ket{1}_B \Big)$</td>
-    </tr>
-    <tr>
-        <td>$01$</td>
-        <td>$\hat{\sigma}_z$</td>
-        <td>$\ket{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B - \Ket{1}_A \Ket{1}_B \Big)$</td>
-    </tr>
-    <tr>
-        <td>$10$</td>
-        <td>$\hat{\sigma}_x$</td>
-        <td>$\ket{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B + \Ket{1}_A \Ket{0}_B \Big)$</td>
-    </tr>
-    <tr>
-        <td>$11$</td>
-        <td>$\hat{\sigma}_x \hat{\sigma}_z$</td>
-        <td>$\ket{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B - \Ket{1}_A \Ket{0}_B \Big)$</td>
-    </tr>
+<tr>
+ <th markdown="1">
+  $$(a_1, a_2)$$
+ </th>
+ <th>
+  Operator
+ </th>
+ <th>
+  Result
+ </th>
+</tr>
+<tr>
+ <td markdown="1">
+  $$00$$
+ </td>
+ <td markdown="1">
+  $$\hat{I}$$
+ </td>
+ <td markdown="1">
+  $$\displaystyle \ket{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B + \Ket{1}_A \Ket{1}_B \Big)$$
+ </td>
+</tr>
+<tr>
+ <td markdown="1">
+  $$01$$
+ </td>
+ <td markdown="1">
+  $$\hat{\sigma}_z$$
+ </td>
+ <td markdown="1">
+  $$\displaystyle \ket{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B - \Ket{1}_A \Ket{1}_B \Big)$$
+ </td>
+</tr>
+<tr>
+ <td markdown="1">
+  $$10$$
+ </td>
+ <td markdown="1">
+  $$\hat{\sigma}_x$$
+ </td>
+ <td markdown="1">
+  $$\displaystyle \ket{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B + \Ket{1}_A \Ket{0}_B \Big)$$
+ </td>
+</tr>
+<tr>
+ <td markdown="1">
+  $$11$$
+ </td>
+ <td markdown="1">
+  $$\hat{\sigma}_x \hat{\sigma}_z$$
+ </td>
+ <td markdown="1">
+  $$\displaystyle \ket{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B - \Ket{1}_A \Ket{0}_B \Big)$$
+ </td>
+</tr>
 </table>
 
-Her actions affect the state on Bob's side $B$ due to entanglement.
-Alice then sends her qubit $A$ to Bob over the quantum channel,
+Her actions affect the state on Bob's side $$B$$ due to entanglement.
+Alice then sends her qubit $$A$$ to Bob over the quantum channel,
 so he has both sides of the entangled pair.
 
 Finally, Bob performs a measurement of his pair in the Bell basis,
 which will yield a Bell state that he can then look up in the table above
-to recover the values of the bits $(a_1, a_2)$.
+to recover the values of the bits $$(a_1, a_2)$$.
 In the end, Alice only sent a single qubit,
 and the rest of the information transfer was via entanglement.