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author | Prefetch | 2022-10-27 20:40:09 +0200 |
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committer | Prefetch | 2022-10-27 20:40:09 +0200 |
commit | 6e70f28ccbd5afc1506f71f013278a9d157ef03a (patch) | |
tree | a8ca7113917f3e0040d6e5b446e4e41291fd9d3a /source/know/concept/superdense-coding/index.md | |
parent | bcae81336764eb6c4cdf0f91e2fe632b625dd8b2 (diff) |
Optimize last images, add proof template, improve CSS
Diffstat (limited to 'source/know/concept/superdense-coding/index.md')
-rw-r--r-- | source/know/concept/superdense-coding/index.md | 63 |
1 files changed, 6 insertions, 57 deletions
diff --git a/source/know/concept/superdense-coding/index.md b/source/know/concept/superdense-coding/index.md index ba6e898..4338205 100644 --- a/source/know/concept/superdense-coding/index.md +++ b/source/know/concept/superdense-coding/index.md @@ -27,63 +27,12 @@ Based on the values of the two classical bits $$(a_1, a_2)$$, Alice performs the following operations on her side $$A$$ of the Bell state: -<table style="width:70%;margin:auto;text-align:center;"> -<tr> - <th markdown="1"> - $$(a_1, a_2)$$ - </th> - <th> - Operator - </th> - <th> - Result - </th> -</tr> -<tr> - <td markdown="1"> - $$00$$ - </td> - <td markdown="1"> - $$\hat{I}$$ - </td> - <td markdown="1"> - $$\displaystyle \ket{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B + \Ket{1}_A \Ket{1}_B \Big)$$ - </td> -</tr> -<tr> - <td markdown="1"> - $$01$$ - </td> - <td markdown="1"> - $$\hat{\sigma}_z$$ - </td> - <td markdown="1"> - $$\displaystyle \ket{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B - \Ket{1}_A \Ket{1}_B \Big)$$ - </td> -</tr> -<tr> - <td markdown="1"> - $$10$$ - </td> - <td markdown="1"> - $$\hat{\sigma}_x$$ - </td> - <td markdown="1"> - $$\displaystyle \ket{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B + \Ket{1}_A \Ket{0}_B \Big)$$ - </td> -</tr> -<tr> - <td markdown="1"> - $$11$$ - </td> - <td markdown="1"> - $$\hat{\sigma}_x \hat{\sigma}_z$$ - </td> - <td markdown="1"> - $$\displaystyle \ket{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B - \Ket{1}_A \Ket{0}_B \Big)$$ - </td> -</tr> -</table> +| $$(a_1, a_2)$$ | **Operator** | **Result** | +| :-: | :-: | :-: | +| $$00$$ | $$\hat{I}$$ | $$\displaystyle \ket{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B + \Ket{1}_A \Ket{1}_B \Big)$$ | +| $$01$$ | $$\hat{\sigma}_z$$ | $$\displaystyle \ket{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{0}_B - \Ket{1}_A \Ket{1}_B \Big)$$ | +| $$10$$ | $$\hat{\sigma}_x$$ | $$\displaystyle \ket{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B + \Ket{1}_A \Ket{0}_B \Big)$$ | +| $$11$$ | $$\hat{\sigma}_x \hat{\sigma}_z$$ | $$\displaystyle \ket{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\Ket{0}_A \Ket{1}_B - \Ket{1}_A \Ket{0}_B \Big)$$ | Her actions affect the state on Bob's side $$B$$ due to entanglement. Alice then sends her qubit $$A$$ to Bob over the quantum channel, |