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diff --git a/source/know/concept/density-of-states/index.md b/source/know/concept/density-of-states/index.md new file mode 100644 index 0000000..5b18537 --- /dev/null +++ b/source/know/concept/density-of-states/index.md @@ -0,0 +1,153 @@ +--- +title: "Density of states" +date: 2021-05-08 +categories: +- Physics +- Statistics +layout: "concept" +--- + +The **density of states** $g(E)$ of a physical system is defined such that +$g(E) \dd{E}$ is the number of states which could be occupied +with an energy in the interval $[E, E + \dd{E}]$. +In fact, $E$ need not be an energy; +it should just be something that effectively identifies the state. + +In its simplest form, the density of states is as follows, +where $\Gamma(E)$ is the number of states with energy +less than or equal to the argument $E$: + +$$\begin{aligned} + g(E) + = \dv{\Gamma}{E} +\end{aligned}$$ + +If the states can be treated as waves, +which is often the case, +then we can calculate the density of states $g(k)$ in +$k$-space, i.e. as a function of the wavenumber $k = |\vb{k}|$. +Once we have $g(k)$, we use the dispersion relation $E(k)$ to find $g(E)$, +by demanding that: + +$$\begin{aligned} + g(k) \dd{k} = g(E) \dd{E} + \quad \implies \quad + g(E) + = g(k) \dv{k}{E} +\end{aligned}$$ + +Inverting the dispersion relation $E(k)$ to get $k(E)$ might be difficult, +in which case the left-hand equation can be satisfied numerically. + + +Define $\Omega_n(k)$ as the number of states with +a $k$-value less than or equal to the argument, +or in other words, the volume of a hypersphere with radius $k$. +Then the $n$-dimensional density of states $g_n(k)$ +has the following general form: + +$$\begin{aligned} + \boxed{ + g_n(k) + = \frac{D}{2^n k_{\mathrm{min}}^n} \: \dv{\Omega_n}{k} + } +\end{aligned}$$ + +Where $D$ is each state's degeneracy (e.g. due to spin), +and $k_{\mathrm{min}}$ is the smallest allowed $k$-value, +according to the characteristic length $L$ of the system. +We divide by $2^n$ to limit ourselves to the sector where all axes are positive, +because we are only considering the magnitude of $k$. + +In one dimension $n = 1$, the number of states within a distance $k$ from the +origin is the distance from $k$ to $-k$ +(we let it run negative, since its meaning does not matter here), given by: + +$$\begin{aligned} + \Omega_1(k) + = 2 k +\end{aligned}$$ + +To get $k_{\mathrm{min}}$, we choose to look at a rod of length $L$, +across which the function is a standing wave, meaning that +the allowed values of $k$ must be as follows, where $m \in \mathbb{N}$: + +$$\begin{aligned} + \lambda = \frac{2 L}{m} + \quad \implies \quad + k = \frac{2 \pi}{\lambda} = \frac{m \pi}{L} +\end{aligned}$$ + +Take the smallest option $m = 1$, +such that $k_{\mathrm{min}} = \pi / L$, +the 1D density of states $g_1(k)$ is: + +$$\begin{aligned} + \boxed{ + g_1(k) + = \frac{D L}{2 \pi} \: 2 + = \frac{D L}{\pi} + } +\end{aligned}$$ + +In 2D, the number of states within a range $k$ of the +origin is the area of a circle with radius $k$: + +$$\begin{aligned} + \Omega_2(k) + = \pi k^2 +\end{aligned}$$ + +Analogously to the 1D case, +we take the system to be a square of side $L$, +so $k_{\mathrm{min}} = \pi / L$ again. +The density of states then becomes: + +$$\begin{aligned} + \boxed{ + g_2(k) + = \frac{D L^2}{4 \pi^2} \:2 \pi k + = \frac{D L^2 k}{2 \pi} + } +\end{aligned}$$ + +In 3D, the number of states is the volume of a sphere with radius $k$: + +$$\begin{aligned} + \Omega_3(k) + = \frac{4 \pi}{3} k^3 +\end{aligned}$$ + +For a cube with side $L$, we once again find $k_{\mathrm{min}} = \pi / L$. +We thus get: + +$$\begin{aligned} + \boxed{ + g_3(k) + = \frac{D L^3}{8 \pi^3} \:4 \pi k^2 + = \frac{D L^3 k^2}{2 \pi^2} + } +\end{aligned}$$ + +All these expressions contain the characteristic length/area/volume $L^n$, +and therefore give the number of states in that region only. +Keep in mind that $L$ is free to choose; +it need not be the physical size of the system. +In fact, we typically want the density of states +per unit length/area/volume, +so we can just set $L = 1$ in our preferred unit of distance. + +If the system is infinitely large, or if it has periodic boundaries, +then $k$ becomes a continuous variable and $k_\mathrm{min} \to 0$. +But again, $L$ is arbitrary, +so a finite value can be chosen. + + + +## References +1. H. Gould, J. Tobochnik, + *Statistical and thermal physics*, 2nd edition, + Princeton. +2. B. Van Zeghbroeck, + [Principles of semiconductor devices](https://ecee.colorado.edu/~bart/book/book/chapter2/ch2_4.htm), 2011, + University of Colorado. |