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+---
+title: "Probability current"
+date: 2021-02-22
+categories:
+- Quantum mechanics
+- Physics
+layout: "concept"
+---
+
+In quantum mechanics, the **probability current** describes the movement
+of the probability of finding a particle at given point in space.
+In other words, it treats the particle as a heterogeneous fluid with density $|\psi|^2$.
+Now, the probability of finding the particle within a volume $V$ is:
+
+$$\begin{aligned}
+ P = \int_{V} | \psi |^2 \ddn{3}{\vb{r}}
+\end{aligned}$$
+
+As the system evolves in time, this probability may change, so we take
+its derivative with respect to time $t$, and when necessary substitute
+in the other side of the Schrödinger equation to get:
+
+$$\begin{aligned}
+ \pdv{P}{t}
+ &= \int_{V} \psi \pdv{\psi^*}{t} + \psi^* \pdv{\psi}{t} \ddn{3}{\vb{r}}
+ = \frac{i}{\hbar} \int_{V} \psi (\hat{H} \psi^*) - \psi^* (\hat{H} \psi) \ddn{3}{\vb{r}}
+ \\
+ &= \frac{i}{\hbar} \int_{V} \psi \Big( \!-\! \frac{\hbar^2}{2 m} \nabla^2 \psi^* + V(\vb{r}) \psi^* \Big)
+ - \psi^* \Big( \!-\! \frac{\hbar^2}{2 m} \nabla^2 \psi + V(\vb{r}) \psi \Big) \ddn{3}{\vb{r}}
+ \\
+ &= \frac{i \hbar}{2 m} \int_{V} - \psi \nabla^2 \psi^* + \psi^* \nabla^2 \psi \ddn{3}{\vb{r}}
+ = - \int_{V} \nabla \cdot \vb{J} \ddn{3}{\vb{r}}
+\end{aligned}$$
+
+Where we have defined the probability current $\vb{J}$ as follows in
+the $\vb{r}$-basis:
+
+$$\begin{aligned}
+ \vb{J}
+ = \frac{i \hbar}{2 m} (\psi \nabla \psi^* - \psi^* \nabla \psi)
+ = \mathrm{Re} \Big\{ \psi \frac{i \hbar}{m} \psi^* \Big\}
+\end{aligned}$$
+
+Let us rewrite this using the momentum operator
+$\vu{p} = -i \hbar \nabla$ as follows, noting that $\vu{p} / m$ is
+simply the velocity operator $\vu{v}$:
+
+$$\begin{aligned}
+ \boxed{
+ \vb{J}
+ = \frac{1}{2 m} ( \psi^* \vu{p} \psi - \psi \vu{p} \psi^*)
+ = \mathrm{Re} \Big\{ \psi^* \frac{\vu{p}}{m} \psi \Big\}
+ = \mathrm{Re} \{ \psi^* \vu{v} \psi \}
+ }
+\end{aligned}$$
+
+Returning to the derivation of $\vb{J}$, we now have the following
+equation:
+
+$$\begin{aligned}
+ \pdv{P}{t}
+ = \int_{V} \pdv{|\psi|^2}{t} \ddn{3}{\vb{r}}
+ = - \int_{V} \nabla \cdot \vb{J} \ddn{3}{\vb{r}}
+\end{aligned}$$
+
+By removing the integrals, we thus arrive at the **continuity equation**
+for $\vb{J}$:
+
+$$\begin{aligned}
+ \boxed{
+ \nabla \cdot \vb{J}
+ = - \pdv{|\psi|^2}{t}
+ }
+\end{aligned}$$
+
+This states that the total probability is conserved, and is reminiscent of charge
+conservation in electromagnetism. In other words, the probability at a
+point can only change by letting it "flow" towards or away from it. Thus
+$\vb{J}$ represents the flow of probability, which is analogous to the
+motion of a particle.
+
+As a bonus, this still holds for a particle in an electromagnetic vector
+potential $\vb{A}$, thanks to the gauge invariance of the Schrödinger
+equation. We can thus extend the definition to a particle with charge
+$q$ in an SI-unit field, neglecting spin:
+
+$$\begin{aligned}
+ \boxed{
+ \vb{J}
+ = \mathrm{Re} \Big\{ \psi^* \frac{\vu{p} - q \vb{A}}{m} \psi \Big\}
+ }
+\end{aligned}$$
+
+
+
+## References
+1. L.E. Ballentine,
+ *Quantum mechanics: a modern development*, 2nd edition,
+ World Scientific.