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Diffstat (limited to 'source/know/concept/residue-theorem/index.md')
| -rw-r--r-- | source/know/concept/residue-theorem/index.md | 10 |
1 files changed, 3 insertions, 7 deletions
diff --git a/source/know/concept/residue-theorem/index.md b/source/know/concept/residue-theorem/index.md index b58e3c2..a0f515e 100644 --- a/source/know/concept/residue-theorem/index.md +++ b/source/know/concept/residue-theorem/index.md @@ -41,11 +41,8 @@ $$\begin{aligned} } \end{aligned}$$ -<div class="accordion"> -<input type="checkbox" id="proof-res-theorem"/> -<label for="proof-res-theorem">Proof</label> -<div class="hidden" markdown="1"> -<label for="proof-res-theorem">Proof.</label> + +{% include proof/start.html id="proof-theorem" -%} From the definition of a meromorphic function, we know that we can decompose $$f(z)$$ like so, where $$h(z)$$ is holomorphic and $$z_p$$ are all its poles: @@ -62,9 +59,8 @@ $$\begin{aligned} &= \oint_C h(z) \dd{z} + \sum_{p} R_p \oint_C \frac{1}{z - z_p} \dd{z} = \sum_{p} R_p \: 2 \pi i \end{aligned}$$ +{% include proof/end.html id="proof-theorem" %} -</div> -</div> This theorem might not seem very useful, but in fact, by cleverly choosing the contour $$C$$, |