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-rw-r--r--source/know/concept/self-energy/definition.avifbin0 -> 6419 bytes
-rw-r--r--source/know/concept/self-energy/definition.png (renamed from source/know/concept/self-energy/selfenergy.png)bin10213 -> 10213 bytes
-rw-r--r--source/know/concept/self-energy/dyson.avifbin0 -> 4139 bytes
-rw-r--r--source/know/concept/self-energy/expansion.avifbin0 -> 4344 bytes
-rw-r--r--source/know/concept/self-energy/expansion.png (renamed from source/know/concept/self-energy/fullgf.png)bin6127 -> 6127 bytes
-rw-r--r--source/know/concept/self-energy/index.md12
6 files changed, 3 insertions, 9 deletions
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diff --git a/source/know/concept/self-energy/index.md b/source/know/concept/self-energy/index.md
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@@ -204,9 +204,7 @@ that exactly $$2^m m!$$ diagrams at each order are topologically equivalent,
so we are left with non-equivalent diagrams only.
Let $$G(b,a) = G_{ba}$$:
-<a href="fullgf.png">
-<img src="fullgf.png" style="width:90%">
-</a>
+{% include image.html file="expansion.png" width="90%" alt="Full expansion of G in Feynman diagrams" %}
A **reducible diagram** is a Feynman diagram
that can be cut in two valid diagrams
@@ -217,9 +215,7 @@ At last, we define the **self-energy** $$\Sigma(y,x)$$
as the sum of all irreducible terms in $$G(b,a)$$,
after removing the two external lines from/to $$a$$ and $$b$$:
-<a href="selfenergy.png">
-<img src="selfenergy.png" style="width:90%">
-</a>
+{% include image.html file="definition.png" width="90%" alt="Definition of self-energy" %}
Despite its appearance, the self-energy has the semantics of a line,
so it has two endpoints over which to integrate if necessary.
@@ -238,9 +234,7 @@ Thanks to this recursive structure,
you can convince youself that $$G(b,a)$$ obeys
a [Dyson equation](/know/concept/dyson-equation/) involving $$\Sigma(y, x)$$:
-<a href="dyson.png">
-<img src="dyson.png" style="width:95%">
-</a>
+{% include image.html file="dyson.png" width="95%" alt="Dyson equation in Feynman diagrams" %}
This makes sense: in the "normal" Dyson equation
we have a one-body perturbation instead of $$\Sigma$$,