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---
title: "Boltzmann relation"
sort_title: "Boltzmann relation"
date: 2021-10-18
categories:
- Physics
- Plasma physics
layout: "concept"
---
In a plasma where the ions and electrons are both in thermal equilibrium,
and in the absence of short-lived induced electromagnetic fields,
their densities $$n_i$$ and $$n_e$$ can be predicted.
By definition, a particle in an [electric field](/know/concept/electric-field/) $$\vb{E}$$
experiences a [Lorentz force](/know/concept/lorentz-force/) $$\vb{F}_e$$.
This corresponds to a force density $$\vb{f}_e$$,
such that $$\vb{F}_e = \vb{f}_e \dd{V}$$.
For the electrons, we thus have:
$$\begin{aligned}
\vb{f}_e
= q_e n_e \vb{E}
= - q_e n_e \nabla \phi
\end{aligned}$$
Meanwhile, if we treat the electrons as a gas
obeying the ideal gas law $$p_e = k_B T_e n_e$$,
then the pressure $$p_e$$ leads to another force density $$\vb{f}_p$$:
$$\begin{aligned}
\vb{f}_p
= - \nabla p_e
= - k_B T_e \nabla n_e
\end{aligned}$$
At equilibrium, we demand that $$\vb{f}_e = - \vb{f}_p$$,
and isolate this equation for $$\nabla n_e$$, yielding:
$$\begin{aligned}
k_B T_e \nabla n_e
= - q_e n_e \nabla \phi
\quad \implies \quad
\nabla n_e
= - \frac{q_e \nabla \phi}{k_B T_e} n_e
= - \nabla \bigg( \frac{q_e \phi}{k_B T_e} \bigg) n_e
\end{aligned}$$
This equation is straightforward to integrate,
leading to the following expression for $$n_e$$,
known as the **Boltzmann relation**,
due to its resemblance to the statistical Boltzmann distribution
(see [canonical ensemble](/know/concept/canonical-ensemble/)):
$$\begin{aligned}
\boxed{
n_e(\vb{r})
= n_{e0} \exp\!\bigg( \!-\! \frac{q_e \phi(\vb{r})}{k_B T_e} \bigg)
}
\end{aligned}$$
Where the linearity factor $$n_{e0}$$ represents
the electron density for $$\phi = 0$$.
We can do the same for ions instead of electrons,
leading to the following ion density $$n_i$$:
$$\begin{aligned}
\boxed{
n_i(\vb{r})
= n_{i0} \exp\!\bigg( \!-\! \frac{q_i \phi(\vb{r})}{k_B T_i} \bigg)
}
\end{aligned}$$
However, due to their larger mass,
ions are much slower to respond to fluctuations in the above equilibrium.
Consequently, after a perturbation,
the ions spend much more time in a transient non-equilibrium state
than the electrons, so this formula for $$n_i$$ is only valid
if the perturbation is sufficiently slow,
allowing the ions to keep up.
Usually, electrons do not suffer the same issue,
thanks to their small mass and fast response.
## References
1. P.M. Bellan,
*Fundamentals of plasma physics*,
1st edition, Cambridge.
2. M. Salewski, A.H. Nielsen,
*Plasma physics: lecture notes*,
2021, unpublished.
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