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-rw-r--r--latex/know/concept/gram-schmidt-method/source.md35
-rw-r--r--latex/know/concept/hilbert-space/source.md13
-rw-r--r--latex/know/concept/partial-fraction-decomposition/source.md12
3 files changed, 46 insertions, 14 deletions
diff --git a/latex/know/concept/gram-schmidt-method/source.md b/latex/know/concept/gram-schmidt-method/source.md
new file mode 100644
index 0000000..b0c7b3b
--- /dev/null
+++ b/latex/know/concept/gram-schmidt-method/source.md
@@ -0,0 +1,35 @@
+% Gram-Schmidt method
+
+
+# Gram-Schmidt method
+
+Given a set of linearly independent non-orthonormal vectors
+$\ket*{V_1}, \ket*{V_2}, ...$ from a Hilbert space, the **Gram-Schmidt method**
+turns them into an orthonormal set $\ket*{n_1}, \ket*{n_2}, ...$ as follows:
+
+1. Take the first vector $\ket*{V_1}$ and normalize it to get $\ket*{n_1}$:
+
+ $$\begin{aligned}
+ \ket*{n_1} = \frac{\ket*{V_1}}{\sqrt{\braket*{V_1}{V_1}}}
+ \end{aligned}$$
+
+2. Begin loop. Take the next non-orthonormal vector $\ket*{V_j}$, and
+ subtract from it its projection onto every already-processed vector:
+
+ $$\begin{aligned}
+ \ket*{n_j'} = \ket*{V_j} - \ket*{n_1} \braket*{n_1}{V_j} - \ket*{n_2} \braket*{n_2}{V_j} - ... - \ket*{n_{j-1}} \braket*{n_{j-1}}{V_{j-1}}
+ \end{aligned}$$
+
+ This leaves only the part of $\ket*{V_j}$ which is orthogonal to
+ $\ket*{n_1}$, $\ket*{n_2}$, etc. This why the input vectors must be
+ linearly independent; otherwise $\ket{n_j'}$ may become zero at some
+ point.
+
+3. Normalize the resulting ortho*gonal* vector $\ket*{n_j'}$ to make it
+ ortho*normal*:
+
+ $$\begin{aligned}
+ \ket*{n_j} = \frac{\ket*{n_j'}}{\sqrt{\braket*{n_j'}{n_j'}}}
+ \end{aligned}$$
+
+4. Loop back to step 2, taking the next vector $\ket*{V_{j+1}}$.
diff --git a/latex/know/concept/hilbert-space/source.md b/latex/know/concept/hilbert-space/source.md
index 7d2ea05..3f6ceb5 100644
--- a/latex/know/concept/hilbert-space/source.md
+++ b/latex/know/concept/hilbert-space/source.md
@@ -41,12 +41,11 @@ other. Otherwise, they would be **linearly dependent**.
A vector space $\mathbb{V}$ has **dimension** $N$ if only up to $N$ of
its vectors can be linearly indepedent. All other vectors in
-$\mathbb{V}$ can then be written as a **linear combination** of these $N$
-so-called **basis vectors**.
+$\mathbb{V}$ can then be written as a **linear combination** of these $N$ **basis vectors**.
Let $\vu{e}_1, ..., \vu{e}_N$ be the basis vectors, then any
vector $V$ in the same space can be **expanded** in the basis according to
-the unique "weights" $v_n$, known as the **components** of the vector $V$
+the unique weights $v_n$, known as the **components** of $V$
in that basis:
$$\begin{aligned}
@@ -89,9 +88,9 @@ Two vectors $U$ and $V$ are **orthogonal** if their inner product
$\braket{U}{V} = 0$. If in addition to being orthogonal, $|U| = 1$ and
$|V| = 1$, then $U$ and $V$ are known as **orthonormal** vectors.
-Orthonormality is a desirable property for basis vectors, so if they are
+Orthonormality is desirable for basis vectors, so if they are
not already orthonormal, it is common to manually derive a new
-orthonormal basis from them using e.g. the Gram-Schmidt method.
+orthonormal basis from them using e.g. the [Gram-Schmidt method](/know/concept/gram-schmidt-method).
As for the implementation of the inner product, it is given by:
@@ -157,7 +156,7 @@ The concept of orthonormality must be also weakened. A finite function
$f(x)$ can be normalized as usual, but the basis vectors $x$ themselves
cannot, since each represents an infinitesimal section of the real line.
-The rationale in this case is that the identity operator $\hat{I}$ must
+The rationale in this case is that action of the identity operator $\hat{I}$ must
be preserved, which is given here in [Dirac notation](/know/concept/dirac-notation/):
$$\begin{aligned}
@@ -172,7 +171,7 @@ $$\begin{aligned}
= \int_a^b \braket{x}{\xi} f(\xi) \dd{\xi}
\end{aligned}$$
-For the latter integral to turn into $f(x)$, it is clear that
+For the latter integral to turn into $f(x)$, it is plain to see that
$\braket{x}{\xi}$ must be a [Dirac delta function](/know/concept/dirac-delta-function/),
i.e $\braket{x}{\xi} = \delta(x - \xi)$:
diff --git a/latex/know/concept/partial-fraction-decomposition/source.md b/latex/know/concept/partial-fraction-decomposition/source.md
index aa03f9c..69428e7 100644
--- a/latex/know/concept/partial-fraction-decomposition/source.md
+++ b/latex/know/concept/partial-fraction-decomposition/source.md
@@ -3,7 +3,7 @@
# Partial fraction decomposition
-*Partial fraction decomposition* or *expansion* is a method to rewrite a
+**Partial fraction decomposition** or **expansion** is a method to rewrite a
quotient of two polynomials $g(x)$ and $h(x)$, where the numerator
$g(x)$ is of lower order than $h(x)$, as a sum of fractions with $x$ in
the denominator:
@@ -21,9 +21,9 @@ $$\begin{aligned}
}
\end{aligned}$$
-Then the constant coefficients $c_n$ can either be found the hard way,
+The constants $c_n$ can either be found the hard way,
by multiplying the denominators around and solving a system of $N$
-equations, or the easy way by using the following trick:
+equations, or the easy way by using this trick:
$$\begin{aligned}
\boxed{
@@ -31,8 +31,7 @@ $$\begin{aligned}
}
\end{aligned}$$
-If $h_1$ is a root with multiplicity $m > 1$, then the sum takes the
-form of:
+If $h_1$ is a root with multiplicity $m > 1$, then the sum takes the form of:
$$\begin{aligned}
\boxed{
@@ -41,8 +40,7 @@ $$\begin{aligned}
}
\end{aligned}$$
-Where $c_{1,j}$ are found by putting the terms on a common denominator,
-e.g.:
+Where $c_{1,j}$ are found by putting the terms on a common denominator, e.g.
$$\begin{aligned}
\frac{c_{1,1}}{x - h_1} + \frac{c_{1,2}}{(x - h_1)^2}