Categories: Nonlinear optics, Optics, Perturbation, Physics, Quantum mechanics.

Multi-photon absorption

Consider a quantum system where there are many eigenstates ∣n⟩\Ket{n}, e.g. atomic orbitals, for an electron to occupy. Suppose an electromagnetic wave passes by, such that its Hamiltonian gets perturbed by H^1\hat{H}_1, given in the electric dipole approximation by:

H^1(t)=−p^⋅Ecos⁡(ωt)≈−p^⋅Ee−iωt\begin{aligned} \hat{H}_1(t) = -\vu{p} \cdot \vb{E} \cos(\omega t) \approx -\vu{p} \cdot \vb{E} e^{-i \omega t} \end{aligned}

Where E\vb{E} is the electric field amplitude, and p^≡qx^\vu{p} \equiv q \vu{x} is the transition dipole moment operator. Here, we have made the rotating wave approximation to neglect the eiωte^{i \omega t} term, because it turns out to be irrelevant in this discussion.

We call the ground state ∣0⟩\Ket{0}, but other than that, the other states need not be sorted by energy. However, we demand that the following holds for all even-numbered states ∣e⟩\Ket{e} and ∣e′⟩\Ket{e'}, and for all odd-numbered (uuneven) states ∣u⟩\Ket{u} and ∣u′⟩\Ket{u'}:

⟨e∣H^1∣e′⟩=⟨u∣H^1∣u′⟩=0⟨e∣H^1∣u⟩≠0\begin{aligned} \matrixel{e}{\hat{H}_1}{e'} = \matrixel{u}{\hat{H}_1}{u'} = 0 \qquad \quad \matrixel{e}{\hat{H}_1}{u} \neq 0 \end{aligned}

This is justified for atomic orbitals thanks to Laporte’s selection rule. Therefore, time-dependent perturbation theory says that the NNth-order coefficient corrections are:

ce(N)(t)=−iℏ∑uodd∫0t⟨e∣H^1(τ)∣u⟩ cu(N−1)(τ) eiωeuτdτcu(N)(t)=−iℏ∑eeven∫0t⟨u∣H^1(τ)∣e⟩ ce(N−1)(τ) eiωueτdτ\begin{aligned} c_e^{(N)}(t) &= -\frac{i}{\hbar} \sum_{u}^{\mathrm{odd}} \int_0^t \matrixel{e}{\hat{H}_1(\tau)}{u} \: c_u^{(N-1)}(\tau) \: e^{i \omega_{eu} \tau} \dd{\tau} \\ c_u^{(N)}(t) &= -\frac{i}{\hbar} \sum_{e}^{\mathrm{even}} \int_0^t \matrixel{u}{\hat{H}_1(\tau)}{e} \: c_e^{(N-1)}(\tau) \: e^{i \omega_{ue} \tau} \dd{\tau} \end{aligned}

Where ωeu=(Ee ⁣− ⁣Eu)/ℏ\omega_{eu} = (E_e \!-\! E_u) / \hbar. For simplicity, the electron starts in the lowest-energy state ∣0⟩\Ket{0}:

c0(0)=1cu(0)=ce≠0(0)=0\begin{aligned} c_0^{(0)} = 1 \qquad \qquad c_u^{(0)} = c_{e \neq 0}^{(0)} = 0 \end{aligned}

Finally, we prove the following useful relation for large tt, involving a Dirac delta function δ\delta:

lim⁡t→∞∣eixt−1x∣2=2π δ(x) t\begin{aligned} \lim_{t \to \infty} \bigg| \frac{e^{i x t} - 1}{x} \bigg|^2 = 2 \pi \: \delta(x) \: t \end{aligned}

First, observe that we can rewrite the fraction using an integral:

eixt−1x=eixt/2eixt/2−e−ixt/2x=ieixt/2∫−t/2t/2eixτdτ\begin{aligned} \frac{e^{i x t} - 1}{x} = e^{i x t / 2} \frac{e^{i x t / 2} - e^{-i x t / 2}}{x} = i e^{i x t / 2} \int_{-t/2}^{t/2} e^{i x \tau} \dd{\tau} \end{aligned}

By taking the limit t→∞t \to \infty, it can be turned into a nascent Dirac delta function:

lim⁡t→∞eixt−1x=lim⁡t→∞ieixt/22π2π∫−∞∞eixτdτ=lim⁡t→∞i2πeixt/2 δ(x)\begin{aligned} \lim_{t \to \infty} \frac{e^{i x t} - 1}{x} = \lim_{t \to \infty} i e^{i x t / 2} \frac{2 \pi}{2 \pi} \int_{-\infty}^{\infty} e^{i x \tau} \dd{\tau} = \lim_{t \to \infty} i 2 \pi e^{i x t / 2} \: \delta(x) \end{aligned}

Consequently, the absolute value squared is as follows:

lim⁡t→∞∣eixt−1x∣2=4π2δ2(x)\begin{aligned} \lim_{t \to \infty} \bigg| \frac{e^{i x t} - 1}{x} \bigg|^2 = 4 \pi^2 \delta^2(x) \end{aligned}

However, a squared delta function δ2\delta^2 is not ideal, so we take a step back:

δ2(x)=δ(x)lim⁡t→∞12π∫−t/2t/2eixτdτ=δ(x)lim⁡t→∞t2π\begin{aligned} \delta^2(x) = \delta(x) \lim_{t \to \infty} \frac{1}{2 \pi} \int_{-t/2}^{t/2} e^{i x \tau} \dd{\tau} = \delta(x) \lim_{t \to \infty} \frac{t}{2 \pi} \end{aligned}

Where we have set x=0x = 0 according to the first delta function. This gives the target:

lim⁡t→∞∣eixt−1x∣2=4π2δ2(x)=2π δ(x) t\begin{aligned} \lim_{t \to \infty} \bigg| \frac{e^{i x t} - 1}{x} \bigg|^2 = 4 \pi^2 \delta^2(x) = 2 \pi \: \delta(x) \: t \end{aligned}

One-photon absorption

To warm up, we start at first-order perturbation theory. Thanks to our choice of initial condition, nothing at all happens to any of the even-numbered states ∣e⟩\Ket{e}:

ce(1)(t)=−iℏ∑uodd∫0t⟨e∣H^1(τ)∣u⟩ cu(0) eiωeuτdτ=0\begin{aligned} c_e^{(1)}(t) &= -\frac{i}{\hbar} \sum_{u}^{\mathrm{odd}} \int_0^t \matrixel{e}{\hat{H}_1(\tau)}{u} \: c_u^{(0)} \: e^{i \omega_{eu} \tau} \dd{\tau} = 0 \end{aligned}

While the odd-numbered states ∣u⟩\Ket{u} have a nonzero correction cu(1)c_u^{(1)}, where pu0=⟨u∣p^∣0⟩\vb{p}_{u0} = \matrixel{u}{\vu{p}}{0}:

cu(1)(t)=−iℏ∫0t⟨u∣H^1(τ)∣0⟩ c0(0) eiωu0τdτ=ipu0⋅Eℏ∫0tei(ωu0−ω)τdτ=ipu0⋅Eℏ[ei(ωu0−ω)τi(ωu0−ω)]0t\begin{aligned} c_u^{(1)}(t) &= -\frac{i}{\hbar} \int_0^t \matrixel{u}{\hat{H}_1(\tau)}{0} \: c_0^{(0)} \: e^{i \omega_{u0} \tau} \dd{\tau} \\ &= i \frac{\vb{p}_{u0} \cdot \vb{E}}{\hbar} \int_0^t e^{i (\omega_{u0} - \omega) \tau} \dd{\tau} \\ &= i \frac{\vb{p}_{u0} \cdot \vb{E}}{\hbar} \bigg[ \frac{e^{i (\omega_{u0} - \omega) \tau}}{i (\omega_{u0} - \omega)} \bigg]_0^t \end{aligned}

Consequently, the first-order correction (in the rotating wave approximation) is given by:

cu(1)(t)≈pu0⋅Eℏei(ωu0−ω)t−1ωu0−ω\begin{aligned} \boxed{ c_u^{(1)}(t) \approx \frac{\vb{p}_{u0} \cdot \vb{E}}{\hbar} \frac{e^{i (\omega_{u0} - \omega) t} - 1}{\omega_{u0} - \omega} } \end{aligned}

Since ∣cu(1)(t)∣2\big| c_u^{(1)}(t) \big|^2 is the probability of finding the electron in ∣u⟩\Ket{u}, its transition rate Ru(1)(t)R_u^{(1)}(t) is as follows, averaged since the beginning t=0t = 0:

Ru(1)(t)=∣cu(1)(t)∣2t=1t∣pu0⋅Eℏ∣2⋅∣ei(ωu0−ω)t−1ωu0−ω∣2\begin{aligned} R_u^{(1)}(t) = \frac{\big| c_u^{(1)}(t) \big|^2}{t} = \frac{1}{t} \bigg| \frac{\vb{p}_{u0} \cdot \vb{E}}{\hbar} \bigg|^2 \cdot \bigg| \frac{e^{i (\omega_{u0} - \omega) t} - 1}{\omega_{u0} - \omega} \bigg|^2 \end{aligned}

For large t→∞t \to \infty, we can use the formula we proved earlier to get Fermi’s golden rule:

Ru(1)=2π∣pu0⋅Eℏ∣2δ(ωu0−ω)\begin{aligned} \boxed{ R_u^{(1)} = 2 \pi \bigg| \frac{\vb{p}_{u0} \cdot \vb{E}}{\hbar} \bigg|^2 \delta(\omega_{u0} - \omega) } \end{aligned}

This well-known formula represents one-photon absorption: it peaks at ωu0=ω\omega_{u0} = \omega, i.e. when one photon ℏω\hbar \omega has the exact energy of the transition ℏωu0\hbar \omega_{u0}. Note that this transition is only possible when ⟨u∣p^∣0⟩≠0\matrixel{u}{\vu{p}}{0} \neq 0, i.e. for any odd-numbered final state ∣u⟩\Ket{u}.

Two-photon absorption

Next, we go to second-order perturbation theory. Thanks to the previous result ce(1)(t)=0c_e^{(1)}(t) = 0, this time all odd-numbered states ∣u⟩\Ket{u} are unaffected:

cu(2)(t)=−iℏ∑eeven∫0t⟨u∣H^1(τ)∣e⟩ ce(1)(τ) eiωueτdτ=0\begin{aligned} c_u^{(2)}(t) &= -\frac{i}{\hbar} \sum_{e}^{\mathrm{even}} \int_0^t \matrixel{u}{\hat{H}_1(\tau)}{e} \: c_e^{(1)}(\tau) \: e^{i \omega_{ue} \tau} \dd{\tau} = 0 \end{aligned}

While the even-numbered states ∣e⟩\Ket{e} have the following correction, using ωeu ⁣+ ⁣ωu0=ωe0\omega_{eu} \!+\! \omega_{u0} = \omega_{e0}:

ce(2)(t)=−iℏ∑uodd∫0t⟨e∣H^1(τ)∣u⟩ cu(1)(τ) eiωeuτdτ=i∑uodd(peu⋅E)(pu0⋅E)ℏ2(ωu0−ω)∫0tei(ωeu+ωu0−2ω)τ−ei(ωeu−ω)τdτ=i∑uodd(peu⋅E)(pu0⋅E)ℏ2(ωu0−ω)[ei(ωe0−2ω)τi(ωe0−2ω)−ei(ωeu−ω)τi(ωeu−ω)]0t\begin{aligned} c_e^{(2)}(t) &= -\frac{i}{\hbar} \sum_{u}^{\mathrm{odd}} \int_0^t \matrixel{e}{\hat{H}_1(\tau)}{u} \: c_u^{(1)}(\tau) \: e^{i \omega_{eu} \tau} \dd{\tau} \\ &= i \sum_{u}^{\mathrm{odd}} \frac{(\vb{p}_{eu} \cdot \vb{E}) (\vb{p}_{u0} \cdot \vb{E})}{\hbar^2 (\omega_{u0} - \omega)} \int_0^t e^{i (\omega_{eu} + \omega_{u0} - 2 \omega) \tau} - e^{i (\omega_{eu} - \omega) \tau} \dd{\tau} \\ &= i \sum_{u}^{\mathrm{odd}} \frac{(\vb{p}_{eu} \cdot \vb{E}) (\vb{p}_{u0} \cdot \vb{E})}{\hbar^2 (\omega_{u0} - \omega)} \bigg[ \frac{e^{i (\omega_{e0} - 2 \omega) \tau}}{i (\omega_{e0} - 2 \omega)} - \frac{e^{i (\omega_{eu} - \omega) \tau}}{i (\omega_{eu} - \omega)} \bigg]_0^t \end{aligned}

The second term represents one-photon absorption between ∣u⟩\Ket{u} and ∣e⟩\Ket{e}. We do not care about that, so we drop it, leaving only the first term:

ce(2)(t)≈∑uodd(peu⋅E)(pu0⋅E)ℏ2(ωu0−ω)ei(ωe0−2ω)t−1ωe0−2ω\begin{aligned} \boxed{ c_e^{(2)}(t) \approx \sum_{u}^{\mathrm{odd}} \frac{(\vb{p}_{eu} \cdot \vb{E}) (\vb{p}_{u0} \cdot \vb{E})}{\hbar^2 (\omega_{u0} - \omega)} \frac{e^{i (\omega_{e0} - 2 \omega) t} - 1}{\omega_{e0} - 2 \omega} } \end{aligned}

As before, we can define a rate Re(2)(t)R_e^{(2)}(t) for all transitions represented by this term:

Re(2)(t)=∣ce(2)(t)∣2t=1t∣∑uodd(peu⋅E)(pu0⋅E)ℏ2(ωu0−ω)∣2⋅∣ei(ωe0−2ω)t−1ωe0−2ω∣2\begin{aligned} R_e^{(2)}(t) = \frac{\big| c_e^{(2)}(t) \big|^2}{t} = \frac{1}{t} \bigg| \sum_{u}^{\mathrm{odd}} \frac{(\vb{p}_{eu} \cdot \vb{E}) (\vb{p}_{u0} \cdot \vb{E})}{\hbar^2 (\omega_{u0} - \omega)} \bigg|^2 \cdot \bigg| \frac{e^{i (\omega_{e0} - 2 \omega) t} - 1}{\omega_{e0} - 2 \omega} \bigg|^2 \end{aligned}

Which for t→∞t \to \infty takes a similar form to Fermi’s golden rule, using the formula we proved:

Re(2)=2π∣∑uodd(peu⋅E)(pu0⋅E)ℏ2(ωu0−ω)∣2δ(ωe0−2ω)\begin{aligned} \boxed{ R_e^{(2)} = 2 \pi \bigg| \sum_{u}^{\mathrm{odd}} \frac{(\vb{p}_{eu} \cdot \vb{E}) (\vb{p}_{u0} \cdot \vb{E})}{\hbar^2 (\omega_{u0} - \omega)} \bigg|^2 \delta(\omega_{e0} - 2 \omega) } \end{aligned}

This represents two-photon absorption, since it peaks at ωe0=2ω\omega_{e0} = 2 \omega: two identical photons ℏω\hbar \omega are absorbed simultaneously to bridge the energy gap ℏωe0\hbar \omega_{e0}. Surprisingly, such a transition can only occur when ⟨e∣p^∣0⟩=0\matrixel{e}{\vu{p}}{0} = 0, i.e. for any even-numbered final state ∣e⟩\Ket{e}. The rate is proportional to ∣E∣4|\vb{E}|^4, so this effect is only noticeable at high light intensities.

Three-photon absorption

For third-order perturbation theory, all even-numbered states ∣e⟩\Ket{e} are unchanged:

ce(3)(t)=−iℏ∑uodd∫0t⟨e∣H^1(τ)∣u⟩ cu(2)(τ) eiωeuτdτ=0\begin{aligned} c_e^{(3)}(t) &= -\frac{i}{\hbar} \sum_{u}^{\mathrm{odd}} \int_0^t \matrixel{e}{\hat{H}_1(\tau)}{u} \: c_u^{(2)}(\tau) \: e^{i \omega_{eu} \tau} \dd{\tau} = 0 \end{aligned}

And the odd-numbered states ∣u⟩\Ket{u} get the following third-order corrections:

cu(3)(t)=−iℏ∑eeven∫0t⟨u∣H^1(τ)∣e⟩ ce(2)(τ) eiωueτdτ=i∑eeven∑u′odd(pue⋅E)(peu′⋅E)(pu′0⋅E)ℏ3(ωu′0−ω)(ωe0−2ω)∫0tei(ωue+ωe0−3ω)τ−ei(ωue−ω)τdτ=i∑eeven∑u′odd(pue⋅E)(peu′⋅E)(pu′0⋅E)ℏ3(ωu′0−ω)(ωe0−2ω)[ei(ωu0−3ω)τi(ωu0−3ω)−ei(ωue−ω)τi(ωue−ω)]0t\begin{aligned} c_u^{(3)}(t) &= -\frac{i}{\hbar} \sum_{e}^{\mathrm{even}} \int_0^t \matrixel{u}{\hat{H}_1(\tau)}{e} \: c_e^{(2)}(\tau) \: e^{i \omega_{ue} \tau} \dd{\tau} \\ &= i \sum_{e}^{\mathrm{even}} \sum_{u'}^{\mathrm{odd}} \frac{(\vb{p}_{ue} \cdot \vb{E}) (\vb{p}_{eu'} \cdot \vb{E}) (\vb{p}_{u'0} \cdot \vb{E})}{\hbar^3 (\omega_{u'0} - \omega) (\omega_{e0} - 2 \omega)} \int_0^t e^{i (\omega_{ue} + \omega_{e0} - 3 \omega) \tau} - e^{i (\omega_{ue} - \omega) \tau} \dd{\tau} \\ &= i \sum_{e}^{\mathrm{even}} \sum_{u'}^{\mathrm{odd}} \frac{(\vb{p}_{ue} \cdot \vb{E}) (\vb{p}_{eu'} \cdot \vb{E}) (\vb{p}_{u'0} \cdot \vb{E})}{\hbar^3 (\omega_{u'0} - \omega) (\omega_{e0} - 2 \omega)} \bigg[ \frac{e^{i (\omega_{u0} - 3 \omega) \tau}}{i (\omega_{u0} - 3 \omega)} - \frac{e^{i (\omega_{ue} - \omega) \tau}}{i (\omega_{ue} - \omega)} \bigg]_0^t \end{aligned}

Once again, the second term is uninteresting, so we drop it and look at the first term only:

cu(3)(t)≈∑eeven∑u′odd(pue⋅E)(peu′⋅E)(pu′0⋅E)ℏ3(ωu′0−ω)(ωe0−2ω)ei(ωu0−3ω)t−1ωu0−3ω\begin{aligned} \boxed{ c_u^{(3)}(t) \approx \sum_{e}^{\mathrm{even}} \sum_{u'}^{\mathrm{odd}} \frac{(\vb{p}_{ue} \cdot \vb{E}) (\vb{p}_{eu'} \cdot \vb{E}) (\vb{p}_{u'0} \cdot \vb{E})} {\hbar^3 (\omega_{u'0} - \omega) (\omega_{e0} - 2 \omega)} \frac{e^{i (\omega_{u0} - 3 \omega) t} - 1}{\omega_{u0} - 3 \omega} } \end{aligned}

The resulting transition rate Ru(3)(t)R_u^{(3)}(t) is found to have the following familiar form:

Ru(3)(t)=∣cu(3)(t)∣2t=1t∣∑eeven∑u′odd(pue⋅E)(peu′⋅E)(pu′0⋅E)ℏ3(ωu′0−ω)(ωe0−2ω)∣2⋅∣ei(ωu0−3ω)t−1ωu0−3ω∣2\begin{aligned} R_u^{(3)}(t) = \frac{\big| c_u^{(3)}(t) \big|^2}{t} = \frac{1}{t} \bigg| \sum_{e}^{\mathrm{even}} \sum_{u'}^{\mathrm{odd}} \frac{(\vb{p}_{ue} \cdot \vb{E}) (\vb{p}_{eu'} \cdot \vb{E}) (\vb{p}_{u'0} \cdot \vb{E})} {\hbar^3 (\omega_{u'0} - \omega) (\omega_{e0} - 2 \omega)} \bigg|^2 \cdot \bigg| \frac{e^{i (\omega_{u0} - 3 \omega) t} - 1}{\omega_{u0} - 3 \omega} \bigg|^2 \end{aligned}

Applying our formula to this yields the following analogue of Fermi’s golden rule:

Ru(3)=2π∣∑eeven∑u′odd(pue⋅E)(peu′⋅E)(pu′0⋅E)ℏ3(ωu′0−ω)(ωe0−2ω)∣2δ(ωu0−3ω)\begin{aligned} \boxed{ R_u^{(3)} = 2 \pi \bigg| \sum_{e}^{\mathrm{even}} \sum_{u'}^{\mathrm{odd}} \frac{(\vb{p}_{ue} \cdot \vb{E}) (\vb{p}_{eu'} \cdot \vb{E}) (\vb{p}_{u'0} \cdot \vb{E})} {\hbar^3 (\omega_{u'0} - \omega) (\omega_{e0} - 2 \omega)} \bigg|^2 \delta(\omega_{u0} - 3 \omega) } \end{aligned}

This represents three-photon absorption, since it peaks at ωu0=3ω\omega_{u0} = 3 \omega: three identical photons ℏω\hbar \omega are absorbed simultaneously to bridge the energy gap ℏωu0\hbar \omega_{u0}. This process is similar to one-photon absorption, in the sense that it can only occur if ⟨u∣p^∣0⟩≠0\matrixel{u}{\vu{p}}{0} \neq 0. The rate is proportional to ∣E∣6|\vb{E}|^6, so this effect only appears at extremely high light intensities.

N-photon absorption

A pattern has appeared in these calculations: in NNth-order perturbation theory, we get a term representing NN-photon absorption, with a transition rate proportional to ∣E∣2N|\vb{E}|^{2N}. Indeed, we can derive infinitely many formulas in this way, although the results become increasingly unrealistic due to the dependence on E\vb{E}.

If NN is odd, only odd-numbered destinations ∣u⟩\Ket{u} are allowed (assuming the electron starts in the ground state ∣0⟩\Ket{0}), and if NN is even, only even-numbered destinations ∣e⟩\Ket{e}. Nothing has been said about the energies of these states (other than ∣0⟩\Ket{0} being the minimum); everything is determined by the matrix elements ⟨f∣p^∣i⟩\matrixel{f}{\vu{p}}{i}.

References

  1. R.W. Boyd, Nonlinear optics, 4th edition, Academic Press.
  2. R. Shankar, Principles of quantum mechanics, 2nd edition, Springer.