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author | Prefetch | 2021-09-09 17:25:09 +0200 |
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committer | Prefetch | 2021-09-09 17:25:09 +0200 |
commit | e85acc31dbf0c244d34a806f5c700990d374f14c (patch) | |
tree | 4c72c71352a3e29a7caf74b1fd5a32094b455353 /content/know/concept/plancks-law | |
parent | ea12abd73dd1e624367935353605a3c1327b5281 (diff) |
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diff --git a/content/know/concept/plancks-law/index.pdc b/content/know/concept/plancks-law/index.pdc new file mode 100644 index 0000000..6e01b9b --- /dev/null +++ b/content/know/concept/plancks-law/index.pdc @@ -0,0 +1,146 @@ +--- +title: "Planck's law" +firstLetter: "P" +publishDate: 2021-09-09 +categories: +- Physics + +date: 2021-09-09T08:12:14+02:00 +draft: false +markup: pandoc +--- + +# Planck's law + +**Planck's law** describes the radiation spectrum of a **black body**: +a theoretical object in thermal equilibrium, +which absorbs photons, +re-radiates them, and then re-absorbs them. + +Since the photon population varies with time, +this is a [grand canonical ensemble](/know/concept/grand-canonical-ensemble/), +and photons are bosons +(see [Pauli exclusion principle](/know/concept/pauli-exclusion-principle/)), +this system must obey the +[Bose-Einstein distribution](/know/concept/bose-einstein-distribution/), +with a chemical potential $\mu = 0$ (due to the freely varying population): + +$$\begin{aligned} + f_B(E) + = \frac{1}{\exp\!(\beta E) - 1} +\end{aligned}$$ + +Each photon has an energy $E = \hbar \omega = \hbar c k$, +so the [density of states](/know/concept/density-of-states/) +is as follows in 3D: + +$$\begin{aligned} + g(E) + = 2 \frac{g(k)}{E'(k)} + = \frac{V k^2}{\pi^2 \hbar c} + = \frac{V E^2}{\pi^2 \hbar^3 c^3} + = \frac{8 \pi V E^2}{h^3 c^3} +\end{aligned}$$ + +Where the factor of $2$ accounts for the photon's polarization degeneracy. +We thus expect that the number of photons $N(E)$ +with an energy between $E$ and $E + \dd{E}$ is given by: + +$$\begin{aligned} + N(E) \dd{E} + = f_B(E) \: g(E) \dd{E} + = \frac{8 \pi V}{h^3 c^3} \frac{E^2}{\exp\!(\beta E) - 1} \dd{E} +\end{aligned}$$ + +By substituting $E = h \nu$, we find that the number of photons $N(\nu)$ +with a frequency between $\nu$ and $\nu + \dd{\nu}$ must be as follows: + +$$\begin{aligned} + N(\nu) \dd{\nu} + = \frac{8 \pi V}{c^3} \frac{\nu^2}{\exp\!(\beta h \nu) - 1} \dd{\nu} +\end{aligned}$$ + +Multiplying by the energy $h \nu$ yields the distribution of the radiated energy, +which we divide by the volume $V$ to get Planck's law, +also called the **Plank distribution**, +describing a black body's radiated spectral energy density per unit volume: + +$$\begin{aligned} + \boxed{ + u(\nu) + = \frac{8 \pi h}{c^3} \frac{\nu^3}{\exp\!(\beta h \nu) - 1} + } +\end{aligned}$$ + + +## Wien's displacement law + +The Planck distribution peaks at a particular frequency $\nu_{\mathrm{max}}$, +which can be found by solving the following equation for $\nu$: + +$$\begin{aligned} + 0 + = u'(\nu) + \quad \implies \quad + 0 + = 3 \nu^2 (\exp\!(\beta h \nu) - 1) - \nu^3 \beta h \exp\!(\beta h \nu) +\end{aligned}$$ + +By defining $x \equiv \beta h \nu_{\mathrm{max}}$, +this turns into the following transcendental equation: + +$$\begin{aligned} + 3 + = (3 - x) \exp\!(x) +\end{aligned}$$ + +Whose numerical solution leads to **Wien's displacement law**, given by: + +$$\begin{aligned} + \boxed{ + \frac{h \nu_{\mathrm{max}}}{k_B T} + \approx 2.822 + } +\end{aligned}$$ + +Which states that the peak frequency $\nu_{\mathrm{max}}$ +is proportional to the temperature $T$. + + +## Stefan-Boltzmann law + +Because $u(\nu)$ represents the radiated spectral energy density, +we can find the total radiated energy $U$ per unit volume by integrating over $\nu$: + +$$\begin{aligned} + U + &= \int_0^\infty u(\nu) \dd{\nu} + = \frac{8 \pi h}{c^3} \int_0^\infty \frac{\nu^3}{\exp\!(\beta h \nu) - 1} \dd{\nu} + \\ + &= \frac{8 \pi h}{\beta^3 h^3 c^3} \int_0^\infty \frac{(\beta h \nu)^3}{\exp\!(\beta h \nu) - 1} \dd{\nu} + = \frac{8 \pi}{\beta^4 h^3 c^3} \int_0^\infty \frac{x^3}{\exp\!(x) - 1} \dd{x} +\end{aligned}$$ + +This definite integral turns out to be $\pi^4/15$, +leading us to the **Stefan-Boltzmann law**, +which states that the radiated energy is proportional to $T^4$: + +$$\begin{aligned} + \boxed{ + U = \frac{4 \sigma}{c} T^4 + } +\end{aligned}$$ + +Where $\sigma$ is the **Stefan-Boltzmann constant**, which is defined as follows: + +$$\begin{aligned} + \sigma + \equiv \frac{2 \pi^5 k_B^4}{15 c^2 h^3} +\end{aligned}$$ + + + +## References +1. H. Gould, J. Tobochnik, + *Statistical and thermal physics*, 2nd edition, + Princeton. |