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1 files changed, 27 insertions, 6 deletions

diff --git a/content/know/concept/superdense-coding/index.pdc b/content/know/concept/superdense-coding/index.pdc
index e50be2b..1a9337c 100644
--- a/content/know/concept/superdense-coding/index.pdc
+++ b/content/know/concept/superdense-coding/index.pdc
@@ -32,12 +32,33 @@ Based on the values of the two classical bits $(a_1, a_2)$,
 Alice performs the following operations on her side $A$
 of the Bell state:
 
-| $(a_1, a_2)$ | Operator $\qquad$ | Result |
-|:--:|:--|:---------|
-| $00$ | $\hat{I}$ | $\ket*{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{0}_B + \ket{1}_A \ket{1}_B \Big)$ |
-| $01$ | $\hat{\sigma}_z$ | $\ket*{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{0}_B - \ket{1}_A \ket{1}_B \Big)$ |
-| $10$ | $\hat{\sigma}_x$ | $\ket*{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{1}_B + \ket{1}_A \ket{0}_B \Big)$ |
-| $11$ | $\hat{\sigma}_x \hat{\sigma}_z$ | $\ket*{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{1}_B - \ket{1}_A \ket{0}_B \Big)$ |
+<table style="width:70%;margin:auto;text-align:center;">
+    <tr>
+        <th>$(a_1, a_2)$</th>
+        <th>Operator</th>
+        <th>Result</th>
+    </tr>
+    <tr>
+        <td>$00$</td>
+        <td>$\hat{I}$</td>
+        <td>$\ket*{\Phi^{+}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{0}_B + \ket{1}_A \ket{1}_B \Big)$</td>
+    </tr>
+    <tr>
+        <td>$01$</td>
+        <td>$\hat{\sigma}_z$</td>
+        <td>$\ket*{\Phi^{-}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{0}_B - \ket{1}_A \ket{1}_B \Big)$</td>
+    </tr>
+    <tr>
+        <td>$10$</td>
+        <td>$\hat{\sigma}_x$</td>
+        <td>$\ket*{\Psi^{+}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{1}_B + \ket{1}_A \ket{0}_B \Big)$</td>
+    </tr>
+    <tr>
+        <td>$11$</td>
+        <td>$\hat{\sigma}_x \hat{\sigma}_z$</td>
+        <td>$\ket*{\Psi^{-}} = \frac{1}{\sqrt{2}} \Big(\ket{0}_A \ket{1}_B - \ket{1}_A \ket{0}_B \Big)$</td>
+    </tr>
+</table>
 
 Her actions affect the state on Bob's side $B$ due to entanglement.
 Alice then sends her qubit $A$ to Bob over the quantum channel,