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-rw-r--r--content/know/concept/calculus-of-variations/index.pdc8
1 files changed, 4 insertions, 4 deletions
diff --git a/content/know/concept/calculus-of-variations/index.pdc b/content/know/concept/calculus-of-variations/index.pdc
index 26c5753..9cae283 100644
--- a/content/know/concept/calculus-of-variations/index.pdc
+++ b/content/know/concept/calculus-of-variations/index.pdc
@@ -251,7 +251,7 @@ meaning they do not depend on any derivatives of any $f_n(x)$:
$$\begin{aligned}
\phi_m(f_1, ..., f_N, x) = 0
- \qquad
+ \qquad \qquad
\int_{x_0}^{x_1} \phi_m(f_1, ..., f_N, x) \dd{x} = C_m
\end{aligned}$$
@@ -261,12 +261,12 @@ by simply redefining the constraint as $\phi_m^0 = \phi_m - C_m = 0$.
To solve this constrained optimization problem for $f_n(x)$,
we introduce [Lagrange multipliers](/know/concept/lagrange-multiplier/) $\lambda_m$.
-In the former case $\lambda_m(x)$ is a function of all $x$, while in the
+In the former case $\lambda_m(x)$ is a function of $x$, while in the
latter case $\lambda_m$ is constant:
$$\begin{aligned}
- \int \lambda_m(x_i) \: \phi_m(\{f_n\}, x) \dd{x} = 0
- \qquad
+ \int \lambda_m(x) \: \phi_m(\{f_n\}, x) \dd{x} = 0
+ \qquad \qquad
\lambda_m \int \phi_m(\{f_n\}, x) \dd{x} = \lambda_m C_m
\end{aligned}$$