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authorPrefetch2023-04-02 16:57:12 +0200
committerPrefetch2023-04-02 16:57:12 +0200
commita8d31faecc733fa4d63fde58ab98a5e9d11029c2 (patch)
treeb8d039b13e026fb68f0bed439a2cb73397c35981 /source/know/concept/bernstein-vazirani-algorithm
parent9b9346d5e54244f3e2859c3f80e47f2de345a2ad (diff)
Improve knowledge base
Diffstat (limited to 'source/know/concept/bernstein-vazirani-algorithm')
-rw-r--r--source/know/concept/bernstein-vazirani-algorithm/index.md5
1 files changed, 3 insertions, 2 deletions
diff --git a/source/know/concept/bernstein-vazirani-algorithm/index.md b/source/know/concept/bernstein-vazirani-algorithm/index.md
index 5f224dc..884cca3 100644
--- a/source/know/concept/bernstein-vazirani-algorithm/index.md
+++ b/source/know/concept/bernstein-vazirani-algorithm/index.md
@@ -76,8 +76,9 @@ $$\begin{aligned}
\frac{1}{\sqrt{2^N}} \sum_{x = 0}^{2^N - 1} (-1)^{s \cdot x} \Ket{x}
\end{aligned}$$
-Then, thanks to the definition of the Hadamard transform,
-a final set of $$H$$-gates leads us to:
+Then, using the definition of the Hadamard transform
+and the fact that it is its own inverse,
+one final set of $$H$$-gates leads us to:
$$\begin{aligned}
\frac{1}{\sqrt{2^N}} \sum_{x = 0}^{2^N - 1} (-1)^{s \cdot x} \Ket{x}